Which answer choice ?

Find the most common ratio 72,12,2, 1/3,1/18

liraira [26]

Answer:

1/6

Step-by-step explanation:

To find the common ratio, you compare a few pairs of consecutive terms, by dividing an element by its predecessor.

12 / 72 = 1/6

2 / 12 = 1 / 6

1/3 / 2 = 1 / 6

The ratio is constant... so that's your common ratio to go from one term to the next.

To go from one term to the next, you have to multiply by 1/6.

7 0

3 years ago

What is the answer for 2/5x5/8 ?

Maru [420]

It would be 1/4 because you would change them to a common denominator then simply them and you get 1/4

7 0

3 years ago

The company Drug Test Success provides a "1-Panel-THC" test for marihuana usage. Among 300 tested subjects, results from 27 subj

Sindrei [870]

Answer:

There is evidence for the claim that less than 10% of the test results are wrong

Step-by-step explanation:

Given that the company Drug Test Success provides a "1-Panel-THC" test for marihuana usage.

Among 300 tested subjects, results from 27 subjects were wrong (either a false positive or a false negative.)

Sample proportion = $\frac{27}{300} \\=0.09$

H0: p = 0.10

Ha: p <0.10

(left tailed test)

p difference = 0.09-0.10 = -0.01

Std error = $\sqrt{0.1*0.9/300} \\=0.005196$

z statistic = -1.9245

p value = 0.027

Since p <0.05 we reject H0

There is evidence for the claim that less than 10% of the test results are wrong

6 0

3 years ago

A random sample of 49 measurements from one population had a sample mean of 15, with sample standard deviation 5. An independent

kotykmax [81]

Answer:

Comparing the p value with the significance level $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.

Step-by-step explanation:

$\bar X_{1}=15$ represent the mean for sample 1

$\bar X_{2}=18$ represent the mean for sample 2

$s_{1}=5$ represent the sample standard deviation for 1

$s_{f}=6$ represent the sample standard deviation for 2

$n_{1}=49$ sample size for the group 2

$n_{2}=64$ sample size for the group 2

$\alpha=0.01$ Significance level provided

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}\neq 0$

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=49+64-2=111$

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$t=\frac{(15-18)-0}{\sqrt{\frac{5^2}{49}+\frac{6^2}{64}}}}=-2.897$

P value

Since is a bilateral test the p value would be:

$p_v =2*P(t_{111}$

Comparing the p value with the significance level $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.

7 0

3 years ago

Domain Range -3 6 5 3 -2. 1

uranmaximum [27]

Hello there!

Domain={-3,5,2}
Range={6,3,1}

Hope this helps

Have a great day/night

3 0

3 years ago