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4 years ago

The Baker Family spent $28 on 5 tickets.

Mathematics

1 answer:

White raven [17]4 years ago

8 0

Answer:

I cannot not give the correct solution, need more context. How many children are there, how many adults are in the family? So I will explain in my explanation.

Step-by-step explanation:

If more context were given, for example: 2 adults and 2 children.

Then the bakers would have bought 2 adult tickets for ___ each

Then the bakers would have bought 3 children's tickets for ___ each

So using what we know we can create an equation:

2A+3C=28,

meaning 2 adult tickets plus 3 children's tickets costs a total of $28.

So we divide 28 by 5, which is the total amount of tickets.

28/5=5.6

So to figure the cost of children's tickets multiply the cost by amount.

3*$5.6=$16.8, C=16.8

To figure out the cost of the adults tickets multiple the cost by the amount.

2*$5.6=$11.2, A=11.2

a) the bakers would have bought 2 adult tickets for 5.6 each.

b) the bakers would have bought 3 children's tickets for 5.6 each.

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PLSS HELP ILL GIVE YOU A BRAINLIEST AND 30 points!

jekas [21]

A :-) 1.) Given - base = 9 cm
height ( alt ) = 12 cm
hypotenuse ( hypo ) = x
Solution -
By Pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( x )^2 = ( 9 )^2 + ( 12 ) ^2
( x )^2 = 81 + 144
( x )^2 = 225
( x ) = _/225
( x ) = 15 cm

.:. The value of x ( hypotenuse ) = 15 cm

2.) Given - base = 10 cm
Height = 24 cm
Hypotenuse = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( x )^2 = ( 10 )^2 + ( 24 )^2
( x )^2 = 100 + 576
( x )^2 = 676
( x ) = _/676
( x ) = 26

.:. The value of x ( hypotenuse ) = 26 cm

3.) Given - base = 3 cm
Height = 7 cm
Hypotenuse = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( x )^2 = ( 3 )^2 + ( 7 )^2
( x )^2 = 9 + 49
( x )^2 = 58
( x ) = _/58
( x ) = 7.6

.:. The value of x ( hypotenuse ) = 7.6 cm

4.) Given - base = 10 cm
Height = 6 cm
Hypotenuse = x
Solution -
By pythagorus theorem
( Hypo )^2 = ( base )^2 + ( alt )^2
( x )^2 = ( 10 )^2 + ( 6 )^2
( x )^2 = 100 + 36
( x )^2 = 136
( x ) = _/136
( x ) = 11.6

.:. The value of x ( hypotenuse ) = 11.6 cm

5.) Given - hypotenuse = 24 cm
height = 6 cm
Base = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( 24 )^2 = ( x )^2 + ( 6 )^2
( x )^2 = ( 6 )^2 - ( 24 )^2
( x )^2 = 36 - 576
( x )^2 = -540
( x ) = _/-540
( x ) = 23.2

.:. The value of x ( base ) = 23.2 cm

6.) Given - base = 1 cm
height = 1 cm
hypotenuse = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( x )^2 = ( 1 )^2 + ( 1 )^2
( x )^2 = 1 + 1
( x )^2 = 2
( x ) = _/2
( x ) = 1.4

.:. The value of x ( hypotenuse ) = 1.4 cm

7.) Given - hypotenuse = 21 cm
height = 8 cm
Base = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( 21 )^2 = ( x )^2 + ( 8 )^2
441 = ( x )^2 + 64
( x )^2 = 64 - 441
( x )^2 = -377
( x ) = _/-377
( x ) = 19.4

.:. The value of x ( base ) = 19.4

8.) given - height = 24 cm
Hypotenuse = 30cm
Base = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( 30 )^2 = ( x )^2 + ( 24 )^2
900 = ( x )^2 + 576
( x )^2 = 576 - 900
( x )^2 = -324
( x ) = _/-324
( x ) = 18

.:. The value of x ( base ) = 18 cm

9.) ( i ) lets find ‘x’
Given - base = 9 cm
height = 5 cm
hypotenuse = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( x )^2 = ( 9 )^2 + ( 5 )^2
( x )^2 = 81 +25
( x )^2 = 106
( x ) = _/106
( x ) = 10.2

.:. The value of x ( hypotenuse )
= 10.2 cm

( ii ) lets find ‘y’
Given - base = 3 cm
height = 5 cm
Hypotenuse = y
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( y )^2 = ( 3 )^2 + ( 5 )^2
( y )^2 = 9 + 25
( y )^2 = 34
( y ) = _/34
( y ) = 5.8

.:. The value of y ( hypotenuse )
= 5.8 cm

4 0

3 years ago

Enter the ordered pair for the vertices for 180°,0)(QRST).

goldfiish [28.3K]

Answer:

The ordered pair for the vertices for r₍₁₈₀ ₀₎(QRST), is given as follows;

Q' = (-1, -3) R' = (-3, 3) S' = (0, 2) T' = (2, -1)

Step-by-step explanation:

The coordinates of he vertices of the triangle QRST are;

Q(1, 3), R(3, -3), S(0, -2), T(-2, 1)

A rotation of a point with coordinates (x, y) 180° about the origin gives;

The coordinate of the point of the preimage before the rotation = (x, y)

The coordinate of the point of the image after the rotation = (-x, -y)

Therefore we have;

The image of point Q(1, 3) after 180° rotation = Q'(-1, -3)

The image of point R(3, -3) after 180° rotation = R'(-3, 3)

The image of point S(0, -2) after 180° rotation = S'(0, 2)

The image of point T(-2, 1) after 180° rotation = T'(2, -1)

The ordered pair for the vertices for r₍₁₈₀ ₀₎(QRST), is therefore, Q'(-1, -3), R'(-3, 3), S'(0, 2), and T'(2, -1);

Q' = (-1, -3) R' = (-3, 3) S' = (0, 2) T' = (2, -1).

6 0

3 years ago

Please help with these two questions

nevsk [136]

Answer:

10. Let m<Y = y.

Then,

m<Y + m<X +m<Z = 180 [ Sum of angles of triangle is 180 degrees]

or, y + (6x-23) + (4x + 9) = 180

or, y + 10x -14 = 180

or, y = 194 - 10x

or, m<Y = 194 - 10x

12. Solution,

a. m<1 = 60 degrees [Each angles of equilateral triangle is equal to 60 degrees]

b. In triangle WYZ,

m<Z + m<ZWY + m<ZYW =180 [Sum of angles of triangle is 180]

or, 138 + m<ZWY +m<ZWY =180 [Base angles of isosceles triangle are equal, i.e. m<ZYW = m <ZWY]

or, 2 (m<ZWY) = 180 -138 = 42

or, m<ZWY = 21 = m<ZYW

or, m<3 = 21 = m<5

c. Solution,

m<XWY = m<2 + m<3 [Addition axiom]

or, 60 = m<2 + 21 [Each angle of equilateral triangle is 60]

or, m<2 = 39

d. Solution,

m<4 + m<5 =60 [<XYW = 60 ]

or, m<4 + 21 = 60

or, m<4 = 39

7 0

3 years ago

Show with a diagram or picture why 1/2 of 60 is not the same as 1/2 24

77julia77 [94]

1 half and 60 is not the same as 1/2 24 because 1/2 60 is bigger than 1/2 and 24

5 0

4 years ago

What is the equation of this line in slope-intercept form?

allochka39001 [22]

Y=-3x-1

bc the y intercept is -1 and the slope is -3

7 0

3 years ago

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