Help!!!!!!!Plz!!!!!!!

Mathematics

1 answer:

Hoochie [10]3 years ago

6 0

Answer:

I'm so confused

Step-by-step explanation:

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Kevin and Randy Muise have a jar containing 68 coins, all of which are either quarters or nickels. The total value of the coins

Bad White [126]

9514 1404 393

Answer:

23 quarters
45 nickels

Step-by-step explanation:

Let q represent the number of quarters. Then the number of nickels is 68-q, and the number of cents in the jar is ...

25q +5(68 -q) = 800

20q +340 = 800 . . . . simplify

20q = 460 . . . . . . . . subtract 340

q = 23 . . . . . . . . . . . divide by 20; this is the number of quarters

68-q = 45 . . . . . . . find the number of nickels

The jar contains 23 quarters and 45 nickels.

4 0

3 years ago

Please be kind and help me with this question!<br> WARNING: only if your good at math thank you #3

Alexxx [7]

First of all, look at the figure, The ABC orientation is changed from clockwise to counterclockwise, so an odd number of reflections are involved.

Second, look at the answer choices. Right away, you notice that the last choice (E) involves two reflections. That cannot be the transformation you see. Since that is what the question is asking for, the appropriate choice for the transformation NOT done is ...

... E. reflection across the x-axis followed by a reflection across the y-axis

_____

I have to admit, I went through each of the choices to see if it would work to produce the image you see. All choices except E will do that. All that work turned out to be unnecessary.

6 0

4 years ago

Find the 10th term if a1=1531 and d=76.

xz_007 [3.2K]

$\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} a_n=n^{th}\ term\\ n=\textit{term position}\\ a_1=\textit{first term}\\ d=\textit{common difference}\\[-0.5em] \hrulefill\\ n= 10\\ a_1=1531\\ d=76 \end{cases} \\\\\\ a_{10}=1531+(10-1)76\implies a_{10}=1531+(9)76\implies a_{10}=1531+684 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill a_{10}=2215~\hfill$