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Ksju [112]
3 years ago
6

Drop the sat and act as a requirement for admission too if officials say

SAT
1 answer:
Masja [62]3 years ago
8 0
Even if it’s not a requirement, wouldn’t applicants still take these tests as a measure to be “ahead” of others
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On the first day of a measles outbreak at a school
Dahasolnce [82]

Answer:

first isolate all infected children

7 0
2 years ago
A sample of oxygen gas is confined at 127°c and 0.80 atm. if volume of the container holding the gas stayed the same, what would
sveticcg [70]

Based on the calculations, the pressure of this gas sample at 27°C is equal to 0.17 atm.

<h3>How to determine the final pressure.</h3>

In order to calculate the final pressure of an ideal gas at constant volume, we would apply Gay Lussac's law.

Mathematically, Gay Lussac's law is given by this formula;

P\;\alpha \;T\\\\P=kT

<u>Where:</u>

  • P is the pressure.
  • T is the temperature.
  • k is the constant of proportionality.

Substituting the given parameters into the formula, we have;

\frac{P_1}{T_1} =\frac{P_2}{T_2} \\\\\frac{0.80}{127} =\frac{P_2}{27} \\\\0.0063 =\frac{P_2}{27}\\\\P_2 = 0.0063 \times 27

Final pressure = 0.17 atm.

Read more on temperature here: brainly.com/question/888898

3 0
2 years ago
Consider the table below and answer the probability question. Write your answer as a percentage rounded to 1 decimal.
N76 [4]

Answer:

P(Joe) = 0.3

P(Joe\ \&\ North\ Side) = 0.2

Explanation:

Solving (a): P(Joe)

To get this probability, we simply add up the items in the column named Joe.

These items are:

Joe: 34 and 70

And the total is:

Joe = 34 + 70

Joe = 104

The overall population of the system is:

Total = 409

So:

P(Joe) = \frac{Joe}{Total}

P(Joe) = \frac{104}{409}

P(Joe) = 0.3

Solving (a): P(Joe and North Side)

To get this probability, we simply get the intersecting element of Joe column and North Side row.

From the table, the intersecting element is:

Joe and North Side: 70

The overall population of the system is:

Total = 409

P(Joe\ \&\ North\ Side) = \frac{Joe\ \&\ North\ Side}{Total}

P(Joe\ \&\ North\ Side) = \frac{70}{409}

P(Joe\ \&\ North\ Side) = 0.2

7 0
3 years ago
refer to the accompanying data set of mean​ drive-through service times at dinner in seconds at two fast food restaurants. const
CaHeK987 [17]

Step-by-step explanation:

Assuming the data is as shown, restaurant X has a mean service time of 180.56, with a standard deviation of 62.6.

The standard error is SE = s/√n = 62.6/√50 = 8.85.

At 95% confidence, the critical value is z = 1.960.

Therefore, the confidence interval is:

180.56 ± 1.960 × 8.85

180.56 ± 17.35

(163, 198)

Restaurant Y has a mean service time of 152.96, with a standard deviation of 49.2.

The standard error is SE = s/√n = 49.2/√50 = 6.96.

At 95% confidence, the critical value is z = 1.960.

Therefore, the confidence interval is:

152.96 ± 1.960 × 6.96

152.96 ± 13.64

(139, 167)

4 0
3 years ago
if a cluster of people stand gazing upward, passersby will often pause and do likewise. this best illustrates:
PSYCHO15rus [73]

Answer:

The Chameleon Affect

Explanation:

5 0
3 years ago
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