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mafiozo [28]
2 years ago
7

On the first day of a measles outbreak at a school

SAT
1 answer:
Dahasolnce [82]2 years ago
7 0

Answer:

first isolate all infected children

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the captain has a probability 3/7 of hitting the pirate ship. the pirate only has one good eye, so he hits the captains ship wit
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9/35

Explanation:

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Match each equation to the line of best fit that it that it models
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y = 4/7x + 2

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Response questions generally focus on
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A survey found that​ women's heights are normally distributed with mean
zheka24 [161]

Answer:

a. 99.30% of the woman meet the height requirement

b.  If all women are eligible except the shortest​ 1% and the tallest​ 2%, then height should be between 58.32 and 68.83

Explanation:

<em>According to the survey</em>, women's heights are normally distributed with mean 63.9 and standard deviation 2.4

a)

A branch of the military requires​ women's heights to be between 58 in and 80 in. We need to find the probabilities that heights fall between 58 in and 80 in in this distribution. We need to find z-scores of the values 58 in and 80 in. Z-score shows how many standard deviations far are the values from the mean. Therefore they subtracted from the mean and divided by the standard deviation:

z-score of 58 in= z=\frac{58-63.9}{2.4} = -2.458

z-score of 80 in= z=\frac{80-63.9}{2.4} = 6.708

In normal distribution 99.3% of the values have higher z-score than -2.458

0% of the values have higher z-score than 6.708. Therefore 99.3% of the woman meet the height requirement.

b)

To find the height requirement so that all women are eligible except the shortest​ 1% and the tallest​ 2%, we need to find the boundary z-score of the

shortest​ 1% and the tallest​ 2%. Thus, upper bound for z-score has to be 2.054 and lower bound is -2.326

Corresponding heights (H) can be found using the formula

2.054=\frac{H-63.9}{2.4}  and

-2.326=\frac{H-63.9}{2.4}

Thus lower bound for height is 58.32 and

Upper bound for height is 68.83

8 0
3 years ago
Two numbers differ by 8 if their product is 713 then the sum of the two numbers is.
const2013 [10]

The sum of the two numbers is equal to 70.

  • Let the first number be x.
  • Let the second number be y.

In this exercise, you're required to find two numbers by translating the word problem into an algebraic expression and then solving for the unknown variables (x and y).

Translating the word problem into an algebraic expression, we have;

Two numbers differ by 8:

x-y=8    ....equation 1.

The product of the two numbers is 713:

xy=713    ....equation 2.

To calculate the sum of the two numbers:

First of all, we would solve for each of the unknown variables (x and y).

From eqn. 1, we have:

x=8+y   ....equation 3.

Substituting eqn. 3 into eqn. 2, we have:

y(y+8)=713\\\\y^2+8y=713\\\\y^2+8y-713=0

Solving the quadratic equation by factorization, we have:

y^2-31y +23y-713=0\\\\y(y-31)+23(y-31)=0\\\\(y+23)(y-31)=0

y = -23 or 31.

For the value of x, when y = 31:

x=8+31

x = 39

Now, we can calculate the sum of the two numbers:

x+y=39+31=70

Read more on word problems here: brainly.com/question/13170908

4 0
2 years ago
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