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bogdanovich [222]
3 years ago
8

Un hotel alquiló 108 habitaciones, dobles e individuales. El costo de habitación doble por noche es $78 y de habitación individu

al $72. El hotel obtuvo $7,839 de ingreso por el alquiler de las habitaciones durante una noche ¿Cuántas habitaciones dobles y cuantas habitaciones sencillas alquiló esa noche?
Mathematics
1 answer:
Triss [41]3 years ago
8 0
I have to assume that you want the answer in Spanish *but without using accents).

Usa las siguientes variables:

d = numero de habitaciones dobles

i = numero de habitaciones individuales

Por la primera premisa:

d + i = 180

Por la segunda premisa, los costos son tales que:

78d + 72i = 7839

Para resolver ese sistema podemos despejar una de las variables de la primera ecucacion y sustituir en la segunda:

i = 180 - d

78d + 72 (180 - d) = 7839

78d + 12960 - 72d = 7839

De aqui ya veo que va a dar un numero negativo para el numero de habitaciones dobles, asi que supongo que algun dato en el enunciado esta equivocado.

6d = 7839 - 12960 = -5121

=> d = -5121 / 6 = - 853.5


Al corregir los datos podras seguir el procedimiento que te he explicado para encontrar la solucion.
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solniwko [45]

Answer:

-24

Step-by-step explanation:

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4 0
3 years ago
What is the correct answer to this
igomit [66]

Answer:

Perimeter = 9700 cm

Step-by-step explanation:

Dimensions of sides are;

12, 2x, 12, 5, 5, circumference of semi circle

Now, the semi circle has a radius of 7. Thus, the diameter = 7 × 2 = 14

We see that x is the diameter. Thus, x = 14

Thus; base of trapezium that is 2x = 2 × 14 = 28

Also, circumference of semi circle = 2πr = 2π × 7 = 44

Thus;

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Perimeter = 97 m

Converting to cm, we multiply by 100 to get;

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Perimeter = 9700 cm

8 0
3 years ago
Quantavius took a hiking with some friends.The friend started early and walked a while before stoping to each lunch.After lunch
kifflom [539]

Answer:

7\frac{3}{8} \ miles

Step-by-step explanation:

Given:

After lunch the friends walked 6 3/4 miles before arriving at the end of the trail.

The trail is 14 1/8 miles long.

Question asked:

How long did the friends walk before lunch ?

Solution:

Let the friends walk before lunch in miles = x

As total length of trail is given 14\frac{1}{8}\ miles , we can conclude:

Total length of trail = The friends walk before lunch in miles  + The friends walk after lunch in miles

14\frac{1}{8} =x+6\frac{3}{4} \\ \frac{14\times8+1}{8}=x+\frac{6\times4+3}{4} \\\frac{113}{8} =x+\frac{27}{4}

Subtracting both side by \frac{27}{4}

\frac{113}{8} -\frac{27}{4} =x+\frac{27}{4}-\frac{27}{4}

Taking LCM of 4 and 8 ,we get 8

\frac{113-54}{8} =x\\\\\frac{59}{8}  =x\\\ \\7\frac{3}{8} = x

Therefore, the friends walk before lunch is 7\frac{3}{8} \ miles.

6 0
4 years ago
a dog runs 54km in just 3days ,it runs 2km more each day . how many kilometers does it run for the first 2 days?
Lesechka [4]

Let x be the distance it runs on the first day, then:-


x + x + 2 + x + 4 = 54


3x + 6 = 54

3x = 54 - 6 = 48

x = 48/3 = 16 km


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7 0
3 years ago
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Ten is the average number of oil tankers arriving each day at a certain port. The facilities at the
vagabundo [1.1K]

Answer:

If 10 is the average then 10 each side would be 20

so that 15 fits into 20 at 3/4

1- 3/4 = 1/4

So the answer is 1/4

Step-by-step explanation:

5 0
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