If Anne gave birth to four males and four females, and they all gave birth the same way again, they would have eight males, but if it were to happen again, there would be 12 males and 12 females in total if you don't count all of the females giving birth EACH to four males and four females. Otherwise it would be 40 males, and 40 females.
We are given with
p2 + 2pq = 0.64
and another formula is
p2 + 2pq + q2 = 1
Substituting
0.64 + q2 = 1
q2 = 1 - 0.64
q2 = 0.36
q = 0.6
Another formula is
p + q = 1
p = 1 - 0.6
p = 0.4
What is asked is 2pq
p2 + 2pq = 0.64
2pq = 0.64 - 0.4^2
2pq = 0.48
There is 48% that has the heterozygous trait.
Answer A+B=C that is what I know.
Step-by-step explanation:
Answer:
d = 1/4
Step-by-step explanation:
Multiply the equation by the inverse of the coefficient of the variable.

Answer:
0
Step-by-step explanation:
The + on the zero means the limit as x approaches 0 from the right side
