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densk [106]
3 years ago
7

−4 − 6 + 2 + 5 + 8 − 3 (8 − 6 − 3) − (−6 − 2 − 5) (9 − 4)(−6 − 3) pls help me

Mathematics
1 answer:
pantera1 [17]3 years ago
3 0

Answer:

-577

Step-by-step explanation:

−4 − 6 + 2 + 5 + 8 − 3 (8 − 6 − 3) − (−6 − 2 − 5) (9 − 4)(−6 − 3)

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A local deli makes turkey sandwiches and salami sandwiches at a weekly ratio of 2 salami sandwiches for every 5 turkey sandwiche
Dahasolnce [82]

Answer:

24

Step-by-step explanation:

Setting x as the number of salami sandwiches:

2/5 = x/60

Cross-multiplying: 5x = 2 × 60

Simplifying: 5x = 120

Division: x = 24

7 0
3 years ago
A quality control engineer is interested in estimating the proportion of defective items coming off a production line. In a samp
fenix001 [56]

Answer:

The lower bound of a 99% C.I for the proportion of defectives = 0.422

Step-by-step explanation:

From the given information:

The point estimate = sample proportion \hat p

\hat p = \dfrac{x}{n}

\hat p = \dfrac{55}{100}

\hat p = 0.55

At Confidence interval of 99%, the level of significance = 1 - 0.99

= 0.01

Z_{\alpha/2} =Z_{0.01/2} \\ \\ = Z_{0.005} = 2.576

Then the margin of error E = Z_{\alpha/2} \times \sqrt{\dfrac{\hat p(1-\hat p)}{n}}

E = 2.576 \times \sqrt{\dfrac{0.55(1-0.55)}{100}}

E = 2.576 \times \sqrt{\dfrac{0.2475}{100}}

E = 2.576 \times0.04975

E = 0.128156

E ≅ 0.128

At 99% C.I for the population proportion p is: \hat p - E

= 0.55 - 0.128

= 0.422

Thus, the lower bound of a 99% C.I for the proportion of defectives = 0.422

6 0
3 years ago
(10x – 2) - (2x - 7)<br> O 8x + 5<br> O 12.2 + 5<br> o 12c - 9<br> O 83 -9
Yuki888 [10]

Answer:

the first one

8x+5

Step-by-step explanation:

10x-2-2x+7= 8x+5

8 0
3 years ago
Factor 8X squared + 10x + 2​
mojhsa [17]

Answer:

2(4x + 1)(x + 1)

Step-by-step explanation:

Given

8x² + 10x + 2 ← factor out 2 from each term

= 2(4x² + 5x + 1)

To factor the quadratic

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 4 × 1 = 4 and sum = + 5

The factors are + 1 and + 4

Use these factors to split the x - term

4x² + x + 4x + 1 ( factor the first/second and third/fourth terms )

= x(4x + 1) + 1 (4x + 1) ← factor out (4x + 1)

= (4x + 1)(x + 1), thus

4x² + 5x + 1 = (4x + 1)(x + 1) and

8x² + 10x + 2 = 2(4x + 1)(x + 1) ← in factored form

3 0
3 years ago
Avi a gymnast weights 40 kg
adell [148]

What is the question?

7 0
3 years ago
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