Question

Can someone help me answer this, thanks

Answer 1

Answer:

$Height = 173.8ft$

Step-by-step explanation:

Given

$\theta = 40^o$

$d = 200ft$ --- distance from building

$h=6ft$--- height of the building

Let the height of the building be H. So:

$\tan(\theta) = \frac{Opposite}{Adjacent}$

$\tan(40) = \frac{H}{200}$

Make H the subject

$H = 200 * \tan(40)$

$H = 167.82$

The required height s:

$Height = H + h$

$Height = 167.82 + 6$

$Height = 173.82ft$

$Height = 173.8ft$ --- approximately