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Dmitry_Shevchenko [17]
3 years ago
8

The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = (x – 10). What is the stan

dard form of the equation for this line? 2x – 5y = –15 2x – 5y = –17 2x + 5y = –15 2x + 5y = –17
Mathematics
2 answers:
taurus [48]3 years ago
7 0
The answer is 2x +5y=-15
ra1l [238]3 years ago
3 0
2x-5y=-17!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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Complete the table above.
4vir4ik [10]

\bf \begin{array}{|c|c|c|ll}
\cline{1-3}
x&y=3x^2&y=3^x\\
\cline{1-3}&&\\
0&\stackrel{3(0)^2}{0}&\stackrel{3^0}{1}\\&&\\
1&\stackrel{3(1)^2}{3}&\stackrel{3^1}{3}\\&&\\
2&\stackrel{3(2)^2}{12}&\stackrel{3^2}{9}\\&&\\
\cline{1-3}
\end{array}

4 0
3 years ago
Some teachers compared how many years they have been teaching.
Alex_Xolod [135]

Answer:

6

Step-by-step explanation:

The range of a data set is the numbers covered by the data. This means that the range is the difference between the minimum and maximum. The minimum is the smallest point, 2, and the maximum is the largest point, 8. Therefore, since 8-2=6, 6 must be the range.

5 0
2 years ago
The expression 7+3x+4 represents the perimeter of the triangle. Simplify the expression.
anyanavicka [17]

Answer:

-3.6

Step-by-step explanation:

Simplifying

7 + 3x + 4 = 0

Reorder the terms:

7 + 4 + 3x = 0

Combine like terms: 7 + 4 = 11

11 + 3x = 0

Solving

11 + 3x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-11' to each side of the equation.

11 + -11 + 3x = 0 + -11

Combine like terms: 11 + -11 = 0

0 + 3x = 0 + -11

3x = 0 + -11

Combine like terms: 0 + -11 = -11

3x = -11

Divide each side by '3'.

x = -3.666666667

Simplifying

x = -3.666666667

4 0
3 years ago
Solve for<br> 20 = 5(x + 1)<br> X =
Nataly [62]

Answer:

x = 3

Step-by-step explanation:

5(x+1) = 20

x+1 = 20/5

or, x+1 = 4

or, x = 4-1

so, x = 3

6 0
2 years ago
Read 2 more answers
Which two values of x are roots of the polynomial below?<br> x2-11x + 15
Alex787 [66]

The two values of roots of the polynomial x^{2}-11 x+15 are \frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}

<u>Solution:</u>

Given, polynomial expression is x^{2}-11 x+15

We have to find the roots of the given expression.

In order to find roots, now let us use quadratic formula.

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Given that x^{2}-11 x+15

Here a = 1, b = -11 and c = 15

On substituting the values we get,

x=\frac{-(-11) \pm \sqrt{(-11)^{2}-4 \times 1 \times 15}}{2 \times 1}

\begin{array}{l}{x=\frac{11 \pm \sqrt{121-60}}{2}} \\\\ {x=\frac{11 \pm \sqrt{61}}{2}} \\\\ {x=\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}}\end{array}

Hence, the roots of given polynomial are \frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}

6 0
3 years ago
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