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2 years ago

HELPPPP

Mathematics

1 answer:

Yuki888 [10]2 years ago

7 0

Dilation about the origin multiplies every coordinate by the scale factor.

C' = 4(-5, 2) = (-20, 8)

A' = 4(-4, 4) = (-16, 16)

T' = 4(-1, 2) = (-4, 8)

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1. What is the slope between the points (2,-5) and (8,3)? *<br><br> Show work please

hjlf

Answer:

$\sf m = \dfrac{4}{3}$

Step-by-step explanation:

Given, $\sf (x_1, ~ y_1)$ = (2, -5) and $\sf (x_2, ~ y_2)$ = (8, 3)

The slope formula is, $\sf m = \dfrac{y_2 - y_1}{x_2 - x_1}$

$\sf m = \dfrac{3 - (-5)}{8 - 2}$

$\sf m = \dfrac{8}{6}$

$\bf m = \dfrac{4}{3}$

6 0

2 years ago

Given: △ABC, m∠A=60° m∠C=45°, AB=8 Find: Perimeter of △ABC, Area of △ABC

jarptica [38.1K]

We are given

△ABC, m∠A=60° m∠C=45°, AB=8

Firstly, we will find all angles and sides

Calculation of angle B:

we know that sum of all angles is 180

m∠A+ m∠B+m∠C=180

we can plug values

60°+ m∠B+45°=180

m∠B=75°

Calculation of BC:

we can use law of sines

$\frac{AB}{sin(C)}=\frac{BC}{sin(A)}$

now, we can plug values

$\frac{8}{sin(45)}=\frac{BC}{sin(60)}$

$BC=\frac{8}{sin(45)} \times sin(60)$

$BC=9.798$

Calculation of AC:

$\frac{AB}{sin(C)}=\frac{AC}{sin(B)}$

now, we can plug values

$\frac{8}{sin(45)}=\frac{AC}{sin(75)}$

$AC=\frac{8}{sin(45)} \times sin(75)$

$AC=10.928$

Perimeter:

$p=AB+BC+AC$

we can plug values

$p=10.928+8+9.798$

$p=28.726$

Area:

we can use formula

$A=\frac{1}{2}AB \times AC \times sin(A)$

now, we can plug values

$A=\frac{1}{2}8 \times 10.928 \times sin(60)$

$A=37.85570$ ...............Answer

6 0

3 years ago

Read 2 more answers

Write the equation of a line that has a m= -5 and passes through the point (-1,4)

svetoff [14.1K]

Answer:

We have a slope and a point, this way, we do not need to find the slope using two points. We can find the line using the Slope Form to turn it into Slope-Intercept Form, also known as "y = mx + b". We can use the Slope Form which is "y - y1 = m(x - x1)". A coordinate is "(x,y)", so that means, "(-1,4)" means that x = -1 and y = 4. We can substitute y1 for 4 and x1 for -1, and m for -5 since m is the slope. Plugging that information into the Slope Form Formula we get "y - 4 = -5(x - (-1))". We know that a negative with a negative turn positive, so we can use this information to change the formula to "y - 4 = -5(x + 1)". Now we distribute and simplify, these steps are shown below.

y - 4 = -5(x + 1)

y - 4 = -5x -5

y - 4 + 4 = -5x - 5 + 4

y = -5x - 1

Now that we have simplified it, we can see that the slope is -5 and the -1 is the y-intercept. To check this is a linear equation is to graph it, or substitute three x-coordinate or y-coordinates and draw a line. In conclusion, the equations is y = -5x - 1.

Step-by-step explanation:

4 0

2 years ago

Could someone help me with number 6 ? The directions say what are the variables? which I know the variables are the height and t

kramer

As the time go the grass height go through increasing and decreasing

6 0

2 years ago

12. Find the area lying above the x - axis and below the parabolic curve y = 4x - x2.

Margarita [4]

First we find the zeroes so we don't take the integral of negative bits

4x-x²
x(4-x)
zeroes at x=0 and x=4
it opens down
so the part we are interested in is the bit between x=0 and x=4

$\int\limits^4_0 {4x-x^2} \, dx =[2x^2- \frac{1}{3}x^3]^4_0=(32- \frac{64}{3})-(0)= 10.6666666666$ or aout 10 and 2/3

C is answer

6 0

2 years ago