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jenyasd209 [6]
3 years ago
15

A scenic overlook which extends over a ravine is shaped like a kite.

Mathematics
1 answer:
Ierofanga [76]3 years ago
7 0
B 40 degrees hope this helps you with your work
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Which figure represents the image of trapezoid LMNP after a reflection across the x-axis? figure A figure B figure C figure D
Andrews [41]

Answer:

figure A

Step-by-step explanation:

it’s in the same cordinates but reflected across the x axis

4 0
3 years ago
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If f(3x − 1) = 6x − 1, find f(x) and f(0)
klio [65]

f(3x - 1) = 6x - 1

Rewrite 6x - 1 as a function of 3x - 1:

6x - 1 = 6x - 2 + 1 = 2(3x - 1) + 1

That is,

f(3x - 1) = 2(3x - 1) + 1

which means

f(x) = 2x + 1

and so

f(0) = 2*0 + 1 = 1

5 0
3 years ago
A concentric-tube heat exchanger cools hot water owing at 1 kg/s from 80C to 30C. It uses air owing at 5 kg/s to perform this co
nordsb [41]

Answer:

The log-mean-temperature-difference is 24.03⁰C

Step-by-step explanation:

First we need to know if the heat exchanger is in parallel flow or counter-flow. However, counter flow arrangement is best used to recover heat.

L.M.T.D for counter flow is given as;

L.M.T.D =\frac{(T_h_f_1 -T_c_f_2)-(T_h_f_2 -T_c_f_1)}{2.3log[\frac{T_h_f_1 -T_c_f_2}{T_h_f_2 -T_c_f_1}]}

where;

Thf₁ is the initial temperature of the hot fluid = 80°C

Tcf₂ is the final temperature of the cold fluid = 51.5°C

Thf₁ - Tcf₂ = 80 - 51.5 = 28.5⁰C

Thf₂ is the final temperature of the hot fluid = 30°C

Tcf₁ is the initial temperature of the cold fluid = 10°C

Thf₂ - Tcf₁ = 30 - 10 = 20⁰C

L.M.T.D = \frac{28.5 -20}{2.3Log[\frac{28.5}{20}]} \\\\L.M.T.D = \frac{8.5}{0.3538} =24.03^oC

Therefore, the log-mean-temperature-difference is 24.03⁰C

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3 years ago
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If 7 men can do a certain job in 12 days, how long would it take 6 mens to do the same job?
-BARSIC- [3]

Answer:

about 10 days

Step-by-step explanation:

4 0
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A high school is putting the finishing touches on their new fitness room and is preparing
Vsevolod [243]

Answer:

bvghb vbub b

Step-by-step explanation:

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