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Greeley [361]
3 years ago
5

Which first step for solving the given system using substitution results in an equation without fractions? Solve for x in the fi

rst equation. Solve for y in the first equation. Solve for x in the second equation. Solve for y in the second equation.
Mathematics
2 answers:
AfilCa [17]3 years ago
7 0

Answer:

b

Step-by-step explanation:

edit:

the one after that is b

A= 1

B= 2

C= below

lianna [129]3 years ago
5 0

Answer:

solve for x in the second equation is correct

Step-by-step explanation:

Here is the complete question

Which first step for solving the given system using substitution results in an equation without fractions?

(2x+6y=7

(6x + 18y = 24.... 2

Solve for x in the first equation,

Solve for y in the first equation,

Solve for x in the second equation

The best equation to she will be equation 2 since all the coefficients are end numbers

Let us make x t subject f the formula from equation 2;

From 2: 6x+18y = 24

Subtract 18y from both sides

6x+18y-18y = 24-18y

6x = 24-18y

Divide through by 6

6x/6 = 24/6 - 18y/6

x = 4-3y.

You can see that the resulting expression of x is not a fraction. Hence solve for x in the second equation is correct

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Answer:

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2 years ago
Apply the Distributive property to rewrite 2(6-x)=3. Choose the correct answer below? *
photoshop1234 [79]

Answer:

12 -2x =3

Step-by-step explanation:

2(6-x)=3.

Distribute

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4 0
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sweet-ann [11.9K]

Answer:

this question answer is 11

8 0
3 years ago
WILL AWARD BRAINLIEST ANSWER
Tpy6a [65]

Answer:

(x - 5)^2 + (y - 7)^2 = 13^2

or

(x - 5)^2 + (y - 7)^2 = 169

Step-by-step explanation:

Well, the center origin of the circle is given (h,k) =  (5,7).

We have to find our radius as they gave us a point. from origin to the edge of the circle.

Using the formula: (x - h)^2 + (y - k)^2 = r^2

Plug in our (h,k) = (5,7) and (x,y) =  (10,19) to solve for radius.

(x - h)^2 + (y - k)^2 = r^2

(10 - (5))^2 + (19 - (7)^2 = r^2

(5)^2 + (12)^2 = r^2

25 + 144  = r^2

r^2 = 169

r = 13

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2 years ago
8. Write an equation of your own that has one real solution. Transform the equation to demonstrate that it has one solution.
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Answer:

2x  {?}^{2}  + 3x - 1 = 0

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