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2 years ago

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A communications company that provides cable, Internet, and phone services, wants to measure its overall customer satisfaction o

f its services. Which measure provides the best information to the company? A. complaints per year B. complaints per year per customer C. complaints per customer per service D. complaints per service

2 answers:

Ilia_Sergeevich [38]2 years ago

4 0

Answer:

Complaints per year

Step-by-step explanation:

To determine overall customer satisfaction, the best measure is complaints per year.

The other measures provide more detailed information that is not necessary for determining overall customer satisfaction.

meriva2 years ago

3 0

Um A idk "Which measure provides the best information to the company?" I guess so

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2 years ago

What is the value of 6/x + 2x^2, when x = 3?

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6/3 + 2(3)^2

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2 years ago

There are 575 fireworks to be shot off in a firework display every minute 12 new fireworks are shot off display write a verbal m

lukranit [14]

Complete question :

There are 575 fireworks to be shot off in a firework display every minute 12 new fireworks are shot off display write a verbal model and algebraic expression to represent the number of fireworks left to be shot off after t minutes.

Answer:

575 - 12t

Step-by-step explanation:

Given the following :

Total number of fireworks = 575

Number of shots per minute = 12

To calculate the number of fireworks left to be shot off after t minutes, The total number of fireworks already shot after the same time interval t in minutes, is first obtained, this is equivalent to (12*t). The result is then subtracted from the total number of fireworks to be shof off.

In algebraic terms

[total number of fireworks on display - (number of shots per minute × t)]

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3 years ago

The design for the palladium window shown includes a semicircular shape at the top. The bottom is formed by squares of equal siz

9966 [12]

Answer:

$(a)\ Area = 3765.32$

$(b)\ Area = 4773$

Step-by-step explanation:

Given

$A_1 = 169in^2$ --- area of each square

$Shade = 4in$

See attachment for window

Solving (a): Area of the window

First, we calculate the dimension of each square

Let the length be L;

So:

$L^2 = A_1$

$L^2 = 169$

$L = \sqrt{169$

$L=13$

The length of two squares make up the radius of the semicircle.

So:

$r = 2 * L$

$r = 2*13$

$r = 26$

The window is made up of a larger square and a semi-circle

Next, calculate the area of the larger square.

16 small squares made up the larger square.

So, the area is:

$A_2 = 16 * 169$

$A_2 = 2704$

The area of the semicircle is:

$A_3 = \frac{\pi r^2}{2}$

$A_3 = \frac{3.14 * 26^2}{2}$

$A_3 = 1061.32$

So, the area of the window is:

$Area = A_2 + A_3$

$Area = 2704 + 1061.32$

$Area = 3765.32$

Solving (b): Area of the shade

The shade extends 4 inches beyond the window.

This means that;

The bottom length is now; Initial length + 8

And the height is: Initial height + 4

In (a), the length of each square is calculated as: 13in

4 squares make up the length and the height.

So, the new dimension is:

$Length = 4 * 13 + 8$

$Length = 60$

$Height = 4*13 + 4$

$Height = 56$

The area is:

$A_1 = 60 * 56 = 3360$

The radius of the semicircle becomes initial radius + 4

$r = 26 + 4 = 30$

The area is:

$A_2 = \frac{3.14 * 30^2}{2} = 1413$

The area of the shade is:

$Area = A_1 + A_2$

$Area = 3360 + 1413$

$Area = 4773$

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2 years ago