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DIA [1.3K]
3 years ago
13

1) Find 25% of 80.

Mathematics
2 answers:
charle [14.2K]3 years ago
7 0
1.20 ----80/4=20
2.----(13/11)x100=answer
3.300% ----9x3=27
4.----29/35 = answer
5.25 ----100/4=25
Alla [95]3 years ago
7 0

1 = 20

2 = 15

3 = 3

4= 15

5 = 2-

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In a completely randomized experimental design, three brands of paper towels were tested for their ability to absorb water. Equa
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Answer:

Yes. At this significance level, there is evidence to support the claim that there is a difference in the ability of the brands to absorb water.

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>The significance level is 0.05.</em>

<em>The data is:</em>

<em>Brand X: 91, 100, 88, 89</em>

<em>Brand Y: 99, 96, 94, 99</em>

<em>Brand Z: 83, 88, 89, 76</em>

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H_0:\mu_x=\mu_y=\mu_z

Alternative hypothesis: the means are not equal

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We have to apply a one-way ANOVA

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Then, we calculate the mean standard error (MSE):

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Now, we calculate the mean square between (MSB), but we previously have to know the sample means and the mean of the sample means:

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The MSB is then:

s^2=\dfrac{\sum(M_i-M)^2}{N-1}\\\\\\s^2=\dfrac{(92-91)^2+(97-91)^2+(84-91)^2}{3-1}\\\\\\s^2=\dfrac{1+36+49}{2}=\dfrac{86}{2}=43\\\\\\\\MSB=ns^2=4*43=172

Now we calculate the F statistic as:

F=MSB/MSE=172/23.78=7.23

The degrees of freedom of the numerator are:

dfn=a-1=3-1=2

The degrees of freedom of the denominator are:

dfd=N-a=3*4-3=12-3=9

The P-value of F=7.23, dfn=2 and dfd=9 is:

P-value=P(F>7.23)=0.01342

As the P-value (0.013) is smaller than the significance level (0.05), the null hypothesis is rejected.

There is evidence to support the claim that there is a difference in the ability of the brands to absorb water.

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