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3 years ago

1) Find 25% of 80.

Mathematics

2 answers:

charle [14.2K]3 years ago

7 0

1.20 ----80/4=20
2.----(13/11)x100=answer
3.300% ----9x3=27
4.----29/35 = answer
5.25 ----100/4=25

Alla [95]3 years ago

7 0

1 = 20

2 = 15

3 = 3

4= 15

5 = 2-

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Find f (2b^2) for (x)=x^2-4x

BlackZzzverrR [31]

Answer:

Step-by-step explanation:

We are given the function:

$f(x) = x^2 - 4x$

And we want to find:

$\displaystyle f(2b^2)$

Substitute:

$\displaystyle f(2b^2) =(2b^2)^2 -4(2b^2)$

And evaluate:

$\displaystyle \begin{aligned} f(2b^2) &=(2b^2)^2 -4(2b^2) \\ &=(4b^4) +(-8b^2) \\ &= 4b^4 - 8b^2 \end{aligned}$

In conclusion, our answer is A.

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3 years ago

11m −4/3=2m+5/3<br><br><br><br>pls tell me this answer is the answer 3

Oksana_A [137]

Answer:

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Step-by-step explanation:

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3 years ago

One winter day, the outside temperature, y, was never below −1°. The inside of a car was always warmer than the temperature outs

sammy [17]

Answer:

The correct option is;

On a coordinate plane, 2 straight lines are shown. The first solid line is horizontal to the y-axis at y = negative 1, Everything above the line is shaded. The second dashed line has a positive slope and goes through (0, negative 4) and (2, negative 2). Everything above and to the left of the line is shaded

Step-by-step explanation:

The inequality representing the first line is y ≥ -1

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3 years ago

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A bread recipe calls for 10 cups of flour. If a bowl already has 4 cups of flour, how many more cups need to be added to the bow

shusha [124]

Answer:

6 more cups

Step-by-step explanation:

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3 years ago

We have two fair three-sided dice, indexed by i = 1, 2. Each die has sides labeled 1, 2, and 3. We roll the two dice independent

Bogdan [553]

Answer:

(a) P(X = 0) = 1/3

(b) P(X = 1) = 2/9

(d) P(X = 3) = 0

(a) P(Y = 0) = 0

(b) P(Y = 1) = 1/3

Step-by-step explanation:

Given:

- Two 3-sided fair die.

- Random Variable X_1 denotes the number you get for rolling 1st die.

- Random Variable X_2 denotes the number you get for rolling 2nd die.

- Random Variable X = X_2 - X_1.

Solution:

- First we will develop a probability distribution of X such that it is defined by the difference of second and first roll of die.

- Possible outcomes of X : { - 2 , -1 , 0 ,1 , 2 }

- The corresponding probabilities for each outcome are:

( X = -2 ): { X_2 = 1 , X_1 = 3 }

P ( X = -2 ): P ( X_2 = 1 ) * P ( X_1 = 3 )

: ( 1 / 3 ) * ( 1 / 3 )

: ( 1 / 9 )

( X = -1 ): { X_2 = 1 , X_1 = 2 } + { X_2 = 2 , X_1 = 3 }

P ( X = -1 ): P ( X_2 = 1 ) * P ( X_1 = 3 ) + P ( X_2 = 2 ) * P ( X_1 = 3)

: ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 )

: ( 2 / 9 )

( X = 0 ): { X_2 = 1 , X_1 = 1 } + { X_2 = 2 , X_1 = 2 } + { X_2 = 3 , X_1 = 3 }

P ( X = -1 ):P ( X_2 = 1 )*P ( X_1 = 1 )+P( X_2 = 2 )*P ( X_1 = 2)+P( X_2 = 3 )*P ( X_1 = 3)

: ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 )

: ( 3 / 9 ) = ( 1 / 3 )

( X = 1 ): { X_2 = 2 , X_1 = 1 } + { X_2 = 3 , X_1 = 2 }

P ( X = 1 ): P ( X_2 = 2 ) * P ( X_1 = 1 ) + P ( X_2 = 3 ) * P ( X_1 = 2)

: ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 )

: ( 2 / 9 )

( X = 2 ): { X_2 = 1 , X_1 = 3 }

P ( X = 2 ): P ( X_2 = 3 ) * P ( X_1 = 1 )

: ( 1 / 3 ) * ( 1 / 3 )

: ( 1 / 9 )

- The distribution Y = X_2,

P(Y=0) = 0

P(Y=1) = 1/3

P(Y=2) = 1/ 3

- The probability for each number of 3 sided die is same = 1 / 3.

7 0

3 years ago