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My name is Ann [436]
3 years ago
15

Gary earns $42,990 per year he is paid weekly he currently has a $456 per month car loan payment and he pays $1277 per year for

auto insurance is one weeks paycheck enough to pay for his monthly auto loan and his monthly cost of insurance? Explain
Mathematics
1 answer:
Ber [7]3 years ago
8 0

Answer:

Yes

Step-by-step explanation:

There are about 52 weeks in a year, 42,990 ÷ 52 = 826.73076 ,

1277 ÷ 12 = 106.41666

826.73076 - 106.41666 = 720.3141

720.3141 - 456 = 264.3141

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Arada [10]
Find the rate of change, (y2-y1)/(x2-x1), from the data given...

(2.16-1.26)/(12-7)=0.18

(1.26-0.72)/(7-4)=0.18

Since the rate is constant, this is a linear equation of the form y=mx+b.  Furthermore, since 0 pencils cost 0, b=0, so the cost of the pencils is simply the number of pencils times 18 cents...

c(p)=0.18p  (cost with respect to pencils is 0.18 times the number of pencils)
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3 years ago
What did the term 4x have in common (have the same) with x,120x, -3x?
Lera25 [3.4K]

Answer:

They're all like terms (x)

7 0
3 years ago
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Solve for t:<br><br> t + 1 = 24<br> A. t = 23<br> B. t = 25<br> C. t = 31<br> D. t = 20
Flauer [41]

Answer:

t = 25

Step-by-step explanation:

T is 25 because you take 1 away from the t+1 side and add the 1 to the 24 side.

3 0
2 years ago
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Michael’s grandmother made two pies for Thanksgiving, a sweet potato pie and a chocolate pie. Each pie had 8 slices. All of the
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4 0
3 years ago
Divid 15 into two parts such that the sum of their reciprocal is 3/10
Klio2033 [76]
From the information obtained from the question, two equations can be created:
 
Let x and z be the two numbers (parts)

\frac{1}{z}   +   \frac{1}{x}  =   \frac{3}{10} .  .  .  . (1)

z  +   x  =  15  .  .  .  . (2)

By transposing (2), make 'z' the subject of the equation
z = 15 - x  .  .  .  . (3)

By substituting (3) into equation (1) to find a value for x
\frac{1}{(15 - x)} + \frac{1}{x} = \frac{3}{10}

\frac{15}{( 15 - x ) ( x )}  =   \frac{3}{10}

3 ( - x^{2}  + 15 x )  =  150

3 x^{2}  - 45x + 150 = 0

⇒  ( x - 5 )  ( x - 10 )  = 0

∴ either ( x - 5) = 0        OR    ( x - 10 ) = 0

Thus x = 5 or x = 10

By substituting the values of x into (2) to find z

     z + (5) = 15       OR      z + (10) = 15

    ⇒      z = 10      OR                 z = 5

So, the two numbers or two parts into which fifteen is divided to yield the desired results are 5 and 10.





5 0
3 years ago
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