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3 years ago

What are the missing operations?

Mathematics

1 answer:

Ronch [10]3 years ago

6 0

Answer:

Solution in photo

Step-by-step explanation:

You might be interested in

Which sequence is arithmetic?

MissTica

Answer:

11, 14, 17, 20

Step-by-step explanation:

An arithmetic sequence has a common difference d between consecutive terms.

Consider 2, 6, 18, 54

6 - 2 = 4, 18 - 6 = 12, 54 - 18 = 36 ← no common difference, not arithmetic

Consider 3, 6, 12, 24

6 - 3 = 3, 12 - 6 = 6, 24 - 12 = 12 ← no common difference, not arithmetic

Consider 11, 14, 17, 20

14 - 11 = 3, 17 - 14 = 3, 20 - 17 = 3 ← common difference of 3, so arithmetic

Consider 7, 11, 13, 18

11 - 7 = 4, 13 - 11 = 2, 18 - 13 = 5 ← no common difference, not arithmetic

The arithmetic sequence is 11, 14, 17, 20

3 0

3 years ago

On Monday, 288 students went on a trip to the zoo. All 7 buses were filled and 8 students had to travel in cars. How many studen

olchik [2.2K]

Answer:

40 kids

Step-by-step explanation:

288 minus the 8 kids that had to hide in cars= 280. 280 divided by the seven busses is 40

8 0

3 years ago

Find the product of 9x(-3x²y-7xz)

kogti [31]

Answer:

$- 27 {x}^{3} y - 63 {x}^{2} z$

Step-by-step explanation:

$9x( - 3 {x}^{2} y - 7xz)$

$= 9x \times ( - 3 {x}^{2} y) + 9x \times ( - 7xz)$

$= - 27 {x}^{3} y - 63 {x}^{2} z$

4 0

3 years ago

What is the expanded form of a number mean?

MatroZZZ [7]

Like if the number is 4,359

You write 4 times 1,000+ 3times 100+ 5times 10+ 9 times 1

3 0

3 years ago

Find cos(2*ABC) 100POINTS

juin [17]

Answer:

$-\dfrac{7}{25}$

Step-by-step explanation:

<u>Trigonometric Identities</u>

$\cos(A \pm B)=\cos A \cos B \mp \sin A \sin B$

<u>Trigonometric ratios</u>

$\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}$

where:

$\theta$ is the angle
O is the side opposite the angle
A is the side adjacent the angle
H is the hypotenuse (the side opposite the right angle)

Using the trig ratio formulas for cosine and sine:

$\cos(\angle ABC)=\dfrac{3}{5}$

$\sin(\angle ABC)=\dfrac{4}{5}$

Therefore, using the trig identities and ratios:

$\begin{aligned}\implies \cos(2 \cdot \angle ABC) & = \cos(\angle ABC + \angle ABC)\\\\& = \cos (\angle ABC) \cos (\angle ABC) - \sin(\angle ABC) \sin (\angle ABC)\\\\& = \cos^2(\angle ABC)-\sin^2(\angle ABC)\\\\& = \left(\dfrac{3}{5}\right)^2-\left(\dfrac{4}{5}\right)^2\\\\& = \dfrac{3^2}{5^2}-\dfrac{4^2}{5^2}\\\\& = \dfrac{9}{25}-\dfrac{16}{25}\\\\& = \dfrac{9-16}{25}\\\\& = -\dfrac{7}{25} \end{aligned}$

7 0

2 years ago

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