2 years ago

Line RS bisects PQ at point R, Find RQ if PQ = 14 cm

Mathematics

1 answer:

Dovator [93]2 years ago

6 0

If PQ is 14, each segment, PR and RQ will be 7.
14 = PR + 7.

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Length of a rectangle is 5 cm longer than the width. Four squares are constructed outside the rectangle such that each of the sq

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The perimeter of rectangle is $18\ cm$

Step-by-step explanation:

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y----> the width of the rectangle

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$x=y+5$ ----> equation A

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substitute the equation A in equation B

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$120=(y+5)y+2(y+5)^{2}+2y^{2}\\ 120=y^{2}+5y+2(y^{2}+10y+25)+2y^{2}\\ 120=y^{2}+5y+2y^{2}+20y+50+2y^{2}\\120=5y^{2}+25y+50\\5y^{2}+25y-70=0$

using a graphing calculator -----> solve the quadratic equation

The solution is

$y=2\ cm$

Find the value of x

$x=y+5 ----> x=2+5=7\ cm$

Find the perimeter of rectangle

$P=2(x+y)=2(7+2)=18\ cm$

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3 years ago

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