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Vaselesa [24]
4 years ago
13

How to solve this math question. We have to solve two step equations

Mathematics
1 answer:
rosijanka [135]4 years ago
5 0
I'm not sure which question you're referring to but.. 
-3r-4>26
Add 4 to both sides
-3r>22
Divide both sides by -3. When you divide by a negative number, flip the inequality. 
r< -22/3
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Alona [7]
Answer : yes



Explanation yes
6 0
3 years ago
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Solve by taking the square root of both sides 3(x-1)^2-162=0
Natali5045456 [20]
We know that: <span>3(x-1)^2-162=0
or (x-1)</span>²= 162:3
and (x-1)²= 54
we <span>take the square root of both sides 
* x-1=</span>√54= 3√6 or x=1+3√6
* x-1= -<span>√54= -3√6 or x=1-3√6
This equation has 2 solutions</span>
7 0
3 years ago
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How can you decide which variable to solve for first when you are solving a linear system by substitution
Helen [10]
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example

if y ou had

(x-3)^2+y=9
you would solve for y becuase it is less tricky

it is all a matter of preference
7 0
3 years ago
Find Dy/dX when x^y×y^x=1​
victus00 [196]

by dy/dx, we'll be assuming that "y" is encapsulating a function, a function in terms of "x".

x^y\cdot y^x=1\implies \stackrel{\textit{\large product rule}}{\stackrel{\textit{chain rule}}{yx^{y-1}(1)}\cdot y^x+x^y\cdot \stackrel{\textit{chain rule}}{xy^{x-1}\cdot \frac{dy}{dx}}}~~ = ~~0 \\\\\\ y^{1+x}x^{y-1}+x^{y+1}y^{x-1}\cdot \cfrac{dy}{dx}=0\implies \cfrac{dy}{dx}=\cfrac{-y^{1+x}x^{y-1}}{x^{y+1}y^{x-1}} \\\\\\ \cfrac{dy}{dx}=-~~ y^{(1+x)-(x-1)}~~x^{(y-1)-(y+1)} \\\\\\ \cfrac{dy}{dx}=-~~ y^2x^{-2}\implies \cfrac{dy}{dx}=\cfrac{-y^2}{x^2}

7 0
3 years ago
PLEASE HELP. I WILL GIVE BRAINLESS
Mila [183]

Answer:

1. 47.1%    2. 69.4%   3. 72.9% 4.  55.6%

Step-by-step explanation:

you just have to add both the numbers and divide the one you are trying to find is liked by the total of both.

ex.

what precent of chicago likes rain?

chicago rain 143   snow 59

143+59=202

143/202=70.7%

7 0
3 years ago
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