Let's start with the fact that this is a function. Each element of Set A is paired with exactly one element of Set B.
This makes Set A the set of inputs and Set B the set of outputs.
There are a lot of other boxes to pick from, so I'm not sure what else you'd need to pick to make your answer correct.
If the co-vertices are (0, 3) and (0, -3) where x is 0 and y has a value, then y is the minor axis. That means that the x axis is the major axis. Because of what the co-vertices are, the center of the ellipse is at the origin. The formula for an ellipse that has a horizontal major axis is
![\frac{(x-h)^2}{a^2}+ \frac{(y-k)^2}{b^2}=1](https://tex.z-dn.net/?f=%20%5Cfrac%7B%28x-h%29%5E2%7D%7Ba%5E2%7D%2B%20%5Cfrac%7B%28y-k%29%5E2%7D%7Bb%5E2%7D%3D1%20%20)
. The a value will always be larger than the b value, therefore, the a value goes under the coordinate that is the major axis. Here, its the x-axis. a is the distance that the outer edge of the ellipse is from the center. It's 8 units away from the center along the x axis and 3 units along the y axis from the center. So a = 8 and a^2 = 64; b = 3 and b^2 = 9. Our formula then is
<span>Simplifying
3x + -8 = 31
Reorder the terms:
-8 + 3x = 31
Solving
-8 + 3x = 31
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '8' to each side of the equation.
-8 + 8 + 3x = 31 + 8
Combine like terms: -8 + 8 = 0
0 + 3x = 31 + 8
3x = 31 + 8
Combine like terms: 31 + 8 = 39
3x = 39
Divide each side by '3'.
x = 13
Simplifying
x = 13</span>
Answer:
The line would be y = 2x + 5
Step-by-step explanation:
To find a parallel line, we first need to note that the slope of the original line is 2. This means the slope of our new line will also be 2 because parallel lines have the same slope.
So we use the slope we found along with the point given in point-slope form. Then we solve for y.
y - y1 = m(x - x1)
y - 11 = 2(x - 3)
y - 11 = 2x - 6
y = 2x + 5
Answer:
3.4
Step-by-step explanation:
I think that you mean "How do you estimate the square root of 12."
1. √12 is between √9 and √16, which are 3 and 4
2. We know that the square root of 12 is between 3 and 4, and we can estimate to the tenth, getting 3.4