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3 years ago

the area of ava rectangular back yard is 325 square yards.if the length of the yards is 13 yards,what is the width of the yard

Mathematics

2 answers:

Novosadov [1.4K]3 years ago

8 0

325 square yards divided by 13 square yards equals 25 square yards.

Viktor [21]3 years ago

6 0

It is given in the question that, The area of ava rectangular back yard is 325 square yards and the length of the yards is 13 yards.

Let the width be w yard .

And area of rectangle is the product of length and width .

So we have

$325 = 13 w$

Dividing both sides by w

$\frac{325}{13} = \frac{13w}{13} => w = 25 yards .$

So the width is 25 yards .

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Answer:

The estimate of the product is about 35 answer C

Step-by-step explanation:

- We use rounding to estimate the product of two fractions

- The mixed number has whole number and fraction

- To round the mixed number we look to the fraction

- If the numerator is half or greater than half the denominator, then we

add the whole number by 1 and cancel the fraction

- If the numerator is less than half the denominator, then we keep the

whole number as it and cancel the fraction

- Ex: If the mixed number is $2\frac{3}{4}$ , 3 is more than

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mixed number $2\frac{3}{4}$ after rounding is 3

- Ex: If the mixed number is $5\frac{1}{4}$ , 1 is less than

half 4 then we will keep 5 as it and cancel the fraction part, the

mixed number $5\frac{1}{4}$ after rounding is 5

* Lets solve the problem

∵ In the part $4\frac{3}{4}$ 3 is more than half 4

∴ The rounding value of $4\frac{3}{4}$ is 5

∵ In the part $7\frac{2}{17}$ 2 is less than half 17

∴ The rounding value of $7\frac{2}{17}$ is 7

∴ $4\frac{3}{4}*7\frac{2}{17}=5*7=35$

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3 years ago

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jeka94

Answer:

y = -0.85 + 0.09x; $49.82

Step-by-step explanation:

1. Calculate Σx, Σy, Σxy, and Σx²

The calculation is tedious but not difficult.

$\begin{array}{rrrr}\mathbf{x} & \mathbf{y} & \mathbf{xy} & \mathbf{x^{2}}\\526 & 52.08 & 27394.08 & 276676\\625& 59.00 & 36875.00 &390625\\589 & 56.12 & 33054.68 & 346921\\409 & 25.72 & 10519.48 & 167281\\489 & 34.12& 16684.68 & 293121\\500 & 53.00 & 26500.00 &250000\\906 & 76.48 & 71102.88 & 820836\\251 &26.08 & 6546.08 & 63001\\595 & 50.60 & 30107.00 & 354025\\719 & 68.52 & 49265.88 & 516961\\\mathbf{5609} & \mathbf{503.72} &\mathbf{308049.76} & \mathbf{3425447}\\\end{array}$

2. Calculate the coefficients in the regression equation

$a = \dfrac{\sum y \sum x^{2} - \sum x \sum xy}{n\sum x^{2}- \left (\sum x\right )^{2}} = \dfrac{503.7 \times 3425447 - 5609 \times 308049.76}{10 \times 3425447- 5609^{2}}\\\\= \dfrac{1725466163 - 1727851103.84}{34254470 - 31460881} = -\dfrac{2384941}{2793589}= \mathbf{-0.8537}$

$b = \dfrac{n\sumx y - \sum x \sumxy}{n\sum x^{2}- \left (\sum x\right )^{2}} = \dfrac{3080498 - 2825365.48}{2793589} = \dfrac{255132}{2793589} = \mathbf{0.09133}$

To two decimal places, the regression equation is

y = -0.85 + 0.09x

3. Prediction

If x = 563,

y = -0.85 + 0.09x = -0.85 + 0.09 × 563 = -0.85 + 50.67 = $49.82

(If we don't round the regression equation to two decimal places, the predicted value is $50.56.)

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