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ehidna [41]
3 years ago
7

Express (3x-4)(x+7)-1/4x squared as a trinomial in standard form

Mathematics
1 answer:
aleksandrvk [35]3 years ago
4 0

Answer: 3x^2+17x-113/4

Step-by-step explanation:

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URGENT HELPP!!!NO LINKS
Scrat [10]

Answer:

25 I believe

Step-by-step explanation:

think has 5 letters

only using it once ofc

5×5= 25

7 0
3 years ago
Solve the equation. Round to the nearest hundredth. Show work.
muminat

Answer:

Final answer is approx x=0.16.

Step-by-step explanation:

Given equation is 2.8\times 13^{4x} +4.8 = 19.3

Now we need to solve equation 2.8\times 13^{4x} +4.8 = 19.3 and round to the nearest hundredth.

2.8\times 13^{4x} +4.8 = 19.3

2.8\times 13^{4x} = 19.3-4.8

2.8\times 13^{4x} = 14.5

13^{4x} = \frac{14.5}{2.8}

13^{4x} = 5.17857142857

\log(13^{4x}) = \log(5.17857142857)

4x \log(13) = \log(5.17857142857)

4x = \frac{\log(5.17857142857)}{\log\left(13\right)}

4x = 0.641154659628

x = \frac{0.641154659628}{4}

x = 0.160288664907

Round to the nearest hundredth.

Hence final answer is approx x=0.16.

4 0
3 years ago
Can anyone figure this out?
rodikova [14]
The rate of change is 4.A linear model
8 0
3 years ago
The Earth is 1.49 × 108 kilometers from the Sun, multiply this expression by the given power of 10.
soldier1979 [14.2K]
1.49 × 10^8

*just move the decimal point 8 places to the right.

149,000,000

hope this helps :)



7 0
3 years ago
Plz do this question if you did I will very appreciated you. plz.​
Nastasia [14]

The area formula of a circle is r^{2} × π.

With that being said, we can solve both problems!

Starting with part A:

-The radius we know is 21cm. From there, we can substitute in our formula with the new value.

21^{2} x π

From there, we can square our radius:

(21 x 21) x π

(441) x π

And finally, we can multiply by pi to get our answer.

(441) x π

1385.44236023

Which rounded to the nearest tenth is 1385.4. Therefore, the area of the porthole is 1385.4 centimetres.

The second part can be followed with the same process, hopefully you understand the concept enough to where you're comfortable solving problems like this on your own. Feel free to reach out if you have any further trouble!

<em>Hope this helped! :)</em>

5 0
3 years ago
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