vertex = (3,- 5 )
given a quadratic in standard form : y = ax² + bx + c ( a ≠ 0 ), then
the x-coordinate of the vertex is
= - 
y = x² - 6x + 4 is in standard form
with a = 1, b = - 6 and c = 4, hence
= - 
= 3
substitute this value into the equation for y- coordinate
y = 3² - 6(3) + 4 = 9 - 18 + 4 = - 5
vertex = (3, - 5 ) → second table
Answer:
y = -(1/2)x + 4
Step-by-step explanation:
Use the standard form on an equation: y = mx + b
A line that is perpendicular has a slope that is the opposite reciprocal of the other line. We also have a point (x, y) that is on the line, so our equation begins as..
1 = -(1/2)(6) + b We must solve for b ( -1/2 is the opposite reciprocal of 2)
1 = -3 + b
4 = b
so our equation is
y = -(1/2)x + 4
Answer:
120 cm^3
Step-by-step explanation:
the edges are 4 cm 5 cm 6 cm
volume of cuboid=l×b×h
=4cm×5cm×6cm
=120cm^3
Answer:
9
Step-by-step explanation:
so we know that its a right triangle and 8 and 
are not the hypotenuse.
the equation for this is 
+
=
with c being the hypotenuse.
+
=
64+17=
81=c
=c
9=c
Wouldn't it be 1/18x?????
