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Ronch [10]
2 years ago
13

A cylinder has an 18-inch diameter and is 15 inches tall. It is filled to the top with water. A 6-inch-diameter ball is placed w

ithin the cylinder, and then the cylinder is filled with water. How much water is in the cylinder? Give your answer in terms of pi. (1 point) 1,162π in3 1,179π in3 1,215π in3 1,251π in3
Mathematics
1 answer:
evablogger [386]2 years ago
7 0

The water in the cylinder will be 1179π in³. Thus, 2nd answer choice is correct.

<h3>What is the volume of a right circular cylinder?</h3>

Suppose that the radius of the considered right circular cylinder be 'r' units.

And let its height be 'h' units.

Then, its volume is given as:

V = \pi r^2 h \: \rm unit^3

A cylinder has an 18-inch diameter and is 15 inches tall. It is filled to the top with water.

A 6-inch-diameter ball is placed within the cylinder, and then the cylinder is filled with water.

We have to find the volume of the empty cylinder and then the volume of the ball.

Subtract the latter from the former.

The volume of the cylinder = πr^2h.  

= π(9 in)²(15 in)

= 1215π in³

Volume of the ball =  (4/3)π(3 in)³

                                = 36π in³

Subtracting

= 1215π in³ - 36π in³

= 1179π in³  

Thus, 2nd answer choice is correct.

Learn more about the volume of cylinder here:

brainly.com/question/12763699

#SPJ1

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Assume that the total overhead variance is x
We are given that the total labor variance is twice the total overhead variance. This means that, the total labor variance is 2x

Total variance can be calculated as follows:
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                          + Total labor variance

We have:
Total variance = $35000
Total materials variance = $14000
Total overhead variance = x
Total labor variance = 2x

Substitute in the equation and solve for x as follows:
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35000 - 14000 = 3x
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x = 21000/3
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Based on the above calculations:
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Answer this please it’s for algebra 2
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Part a)

P(junior) = (number of juniors)/(number total)

P(junior) = 235/705

P(junior) = 1/3 exactly

P(junior) = 0.33333 approximately

======================================

Part b)

P(freshman and LG) = (number of freshman who have LG)/(number total)

P(freshman and LG) = 70/705

P(freshman and LG) = 14/141 exactly

P(freshman and LG) = 0.09929 approximately

======================================

Part c)

n(junior) = number of juniors = 235

n(samsung) = number of people who have samsung = 274

n(junior and samsung) = number of juniors who have samsung = 93

----

n(junior or samsung) = n(junior)+n(samsung)-n(junior and samsung)

n(junior or samsung) = 235+274-93

n(junior or samsung) = 416

----

P(junior or samsung) = n(junior or samsung)/n(total)

P(junior or samsung) = 416/705 exactly

P(junior or samsung) = 0.59007 approximately

======================================

Part d)

n(sophomore and apple) = number of sophomores who have apple

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P(sophomore | apple) = n(sophomore and apple)/n(apple)

P(sophomore | apple) = 80/261 exactly

P(sophomore | apple) = 0.30651 approximately

======================================

Part e)

define the events

A = junior who has apple

B = junior who has samsung

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n(A or B) = n(A) + n(B) ... A and B assumed mutually exclusive

n(A or B) = 87+93

n(A or B) = 180

n(C) = 235

P( (Apple or Samsung) | Junior ) = n(A or B)/n(C)

P( (Apple or Samsung) | Junior ) = 180/235

P( (Apple or Samsung) | Junior ) = 36/47 exactly

P( (Apple or Samsung) | Junior ) = 0.76596 approximately

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