Answer:
There's a parking lot that is 600m² big. The lot must be able to hold at least 3 buses and 10 cars.
Each car takes up 6m² and each bus takes up 30m².
However, there can only be 60 vehicles in the lot at any given time.
The cost to park in the lot is $2.50 per day for cars and $7.50 per day for buses. The lot must make at least $75 each day to break even.
What is a possible car to bus ratio that would allow the lot to make profit?
Explanation:
This is easily solvable with a for loop. Something like:
(I assume c++)
#include <iostream>
#include <string>
int main() {
take_input: //tag
std::string input;
cin >> input; //take the input
int spaceCount = 0;
char checking;
for(unsigned int i = 0; i == input.length(); ++i) {
checking = spaceCount[i];
if(checking == ' ')
spaceCount++;
}
if(spaceCount >= 1 && input.length >= 5)
std::cout << "Your name is " + input;
else
goto take_input; // reasks for input if the conditions are not met
return 0;
};
**remove all spaces before using the code, the if statements are messed up
To indicate which program is needed to open it
