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xxMikexx [17]
3 years ago
14

How can polygons be considered a subcategory of two-dimensional figures? PLEASE HELP THIS IS DUE TOMORROW!!!!!!!!!

Mathematics
1 answer:
gregori [183]3 years ago
7 0
Two-dimensional figures are one category and polygons are a separate category that falls under two-dimensional because 2D(two dimensional) figures are figures that do not have a volume so they are flat. Polygons are flat 2D shapes that have straight lines and all lines are closed, meaning that they don't have any disconnected lines. Polygons are a subcategory of 2D figures because they carry all traits of 2D figures but also have special ones of their own. Examples of polygons are squares, rectangles, and triangles. Examples of nonpolygons but still are 2D figures are circles, ovals, and any other flat shape.
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How can (1/2)x-5=(1/3)x+6 be set up as a system of equations?
leonid [27]

Answer:

 C)

  • 2y-x=-10
  • 3y-x=18

Step-by-step explanation:

Set each side of the equation equal to y, then rearrange to standard form.

  (1/2)x -5 = y . . . left side of the equal sign

  x -10 = 2y . . . . multiply by 2

  -10 = 2y -x . . . . subtract x

__

  (1/3)x +6 = y . . . right side of the equal sign

  x +18 = 3y . . . . . multiply by 3

  18 = 3y -x . . . . . subtract x

The corresponding system of equations is ...

  • 2y -x = -10
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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
Ments
maw [93]

The sector area and the arc length are 34.92 square inches and 13.97 inches, respectively

<h3>How to find a sector area, and arc length?</h3>

For a sector that has a central angle of θ, and a radius of r;

The sector area, and the arc length are:

A = \frac{\theta}{360} * \pi r^2 --- sector area

L = \frac{\theta}{360} * 2\pi r ---- arc length

<h3>How to find the given sector area, and arc length?</h3>

Here, the given parameters are:

Central angle, θ = 160

Radius, r = 5 inches

The sector area is

A = \frac{\theta}{360} * \pi r^2

So, we have:

A = \frac{160}{360} * \frac{22}{7} * 5^2

Evaluate

A = 34.92

The arc length is:

L = \frac{\theta}{360} * 2\pi r

So, we have:

L = \frac{160}{360} * 2 * \frac{22}{7} * 5

L = 13.97

Hence, the sector area and the arc length are 34.92 square inches and 13.97 inches, respectively

Read more about sector area and arc length at:

brainly.com/question/2005046

#SPJ1

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2 years ago
Over 12 months, the value of Mrs. Marino's stocks dropped
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The average monthly change is -36 every 12 months i think ‍♀️
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3 years ago
1. What would be the first step in solving the equation below for r ?
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The first step into solving this equation should be, c dividing by both sides
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