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4 years ago

Find the distance d. (2,4) and (7,2)

Mathematics

1 answer:

taurus [48]4 years ago

8 0

Answer:

$\large\boxed{d=\sqrt{29}}$

Step-by-step explanation:

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have the points (2, 4) and (7, 2). substitute:

$d=\sqrt{(7-2)^2+(2-4)^2}=\sqrt{5^2+(-2)^2}=\sqrt{25+4}=\sqrt{29}$

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Help me with this question

soldi70 [24.7K]

Radius=4.2m

$\\ \bull\tt\dashrightarrow Diameter=2(Radius)$

$\\ \bull\tt\dashrightarrow Diameter=2(4.2)$

$\\ \bull\tt\dashrightarrow Diameter=8.2m$

3 0

3 years ago

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Find the indicated limit, if it exists.(7 points)

Alecsey [184]

Answer:

Step-by-step explanation:

The left hand limit is when we approach zero from left. We use the function on this domain in finding the limit.

$\lim_{x \to 0^-} f(x)=7-x^2$

$\lim_{x \to 0^-} f(x)=7-(0)^2=7$

The right hand limit is

$\lim_{x \to 0^+} f(x)=10x+7$

$\lim_{x \to 0^+} f(x)=10(0)+7=7$

Since the left hand limit equals the right hand limit;

$\lim_{x \to 0} f(x)=7$

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3 years ago

Simplify the expression(a4−6a2b2+ b4)−(−2a4+5a2b2+ 3b4) and hence, find its value for a = 2and b = −1.

ELEN [110]

Answer:

(a) $3a^4 - 11a^2b^2 -2b^4$

(b) $3a^4 - 11a^2b^2 -2b^4= 2$

Step-by-step explanation:

Given

$(a^4 - 6a^2b^2+ b^4) - (-2a^4+5a^2b^2+ 3b^4)$

Solving (a): Simplify

$(a^4 - 6a^2b^2+ b^4) - (-2a^4+5a^2b^2+ 3b^4)$

Open brackets

$a^4 - 6a^2b^2+ b^4 +2a^4-5a^2b^2- 3b^4$

Collect Like Terms

$a^4 +2a^4- 6a^2b^2-5a^2b^2+ b^4 - 3b^4$

Simplify Like Terms

$3a^4 - 11a^2b^2 -2b^4$

Solving (b): Simplify when a = 2 and b = -1

$3a^4 - 11a^2b^2 -2b^4$

$3*(2)^4 - 11*(2^2)*(-1)^2 -2*(-1)^4$

$3 * 16 - 11 * 4 * 1 - 2 * 1$

$48 - 44 - 2$

$= 2$

Hence:

$3a^4 - 11a^2b^2 -2b^4= 2$

4 0

3 years ago

It takes Morgan 1/8

ahrayia [7]

It will take her 6 hours because
3/4=6/8 hours
1/8= 1 hour
I hope this was helpful

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3 years ago

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Please help me with this u don’t have a clue.

maksim [4K]

Answer:

Im so sorry i cant help

Step-by-step explanation:

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3 years ago