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3 years ago

In triangle ABC, the measure of angle BAC = 5x + 8, the measure of angle ABC = 6x + 22, and the measure of angle BCA = 3x − 25.

Mathematics

1 answer:

klemol [59]3 years ago

5 0

I hope this helps you

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I can't see these pictures so write them in numbers

RideAnS [48]

So uhh what is your question?

5 0

3 years ago

Read 2 more answers

Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En

ArbitrLikvidat [17]

Answer:

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , c) $x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$ , $y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$ .

Step-by-step explanation:

The equation of the circle is:

$x^{2} + (y-1)^{2} = 16$

After some algebraic and trigonometric handling:

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1$

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t$

Where:

$\frac{x}{4} = \cos t$

$\frac{y-1}{4} = \sin t$

Finally,

$x = 4\cdot \cos t$

$y = 1 + 4\cdot \sin t$

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

c) $x = 4\cdot \cos t''$ , $y = 1 + 4\cdot \sin t''$

Where:

$4\cdot \cos t' = 0$

$1 + 4\cdot \sin t' = 5$

The solution is $t' = \frac{\pi}{2}$

The parametric equations are:

$x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$

$y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$

7 0

3 years ago

How do u solve P=IRT solve for t

Roman55 [17]

You said that P = I · R · T

Divide each side by I · R : P / (I·R) = T

3 0

3 years ago

Can yall please help me

WITCHER [35]

D is correct. U is incenter of the triangle.

8 0

2 years ago

Two boats started to move towards each other from two docks, located 30 miles apart. One boat moved at a speed of 3 miles per ho

blagie [28]

Answer:

3.333 hours

Step-by-step explanation:

Given the total distance is 30 miles, and boat 1 travels at 3 mph and boat 2 travels at 6 mph, and the time for both is the same. Distance is speed S times time T so

30 = D(boat 1) + D(boat 2)

30 = (S1 * T) + (S2 * T)

30 = 3T + 6T

30 = 9T

3.333 = T

5 0

2 years ago