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sveticcg [70]
3 years ago
10

What are the coordinates of D’

Mathematics
1 answer:
agasfer [191]3 years ago
3 0

Answer:

(-2,-1)

Step-by-step explanation:

Reflection across the x-axis is: (x,y)\rightarrow(x,-y)

We need to multiply the y-value of the pre-image by negative one to get reflected across the x-axis.

1 * -1 = -1

So:

(-2,1)\rightarrow(-2,-1)

D' should be (-2,-1).

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Find the area of the composite shapes. (picture)
aliya0001 [1]

Answer:

6 x 4 x 1/2(basically just dividing by 2) = 12

10 x 6 = 60

60 + 12 = 72 m^2 is your answer

3 0
3 years ago
(2sin60°)(3tan60°)—(4tan45°)(2cos45°)​
Dimas [21]

Answer:

9 - 4\sqrt{2}

Step-by-step explanation:

sin60° = \frac{\sqrt{3} }{2}

tan60° = \sqrt{3}

tan45° = 1

cos45° = \frac{1}{\sqrt{2} }

(2sin60°)(3tan60°) - (4tan45°)(2cos45°)

now substitute the values of each trigonometrical angles

(2*\frac{\sqrt{3} }{2} )(3*\sqrt{3} ) - (4*1)(2*\frac{1}{\sqrt{2} } )

\sqrt{3}  * (3\sqrt{3}) - 4*(\frac{2}{\sqrt{2} } )

3*3 - 4*\frac{2}{\sqrt{2} } *\frac{\sqrt{2} }{\sqrt{2} }

9 - 4 *\frac{2\sqrt{2} }{2}

9 - 4 * \sqrt{2}

9 - 4\sqrt{2}

5 0
3 years ago
What is the solution of the system of equations? Enter the solution as an ordered pair (use decimal rounded to the nearest hundr
Nuetrik [128]
32+54=86-10=76-25= 51
4 0
3 years ago
the surface area of a cuboid is 95cm² and its lateral surface area is 63cm². find the area of its base​
wel

Answer:

The Area of the base is 16 cm² .

Step-by-step explanation:

Given as :

The surface area of the cuboid = x = 95 cm²

The lateral surface area of the cuboid = y = 63 cm²

Let The Area of the base = z cm²

Now, Let The length of cuboid = l cm

The breadth of cuboid = b cm

The height of cuboid = h cm

<u>According to question</u>

∵ The surface area of the cuboid = 2 ×(length × breadth + breadth × height + height × length)

Or, x = 2 ×(l × b + b × h + h × l)

Or, 95 =  2 ×(l × b + b × h + h × l)

Or,  (l × b + b × h + h × l) = \dfrac{95}{2}          ....1

<u>Similarly</u>

∵lateral surface area of the cuboid = 2 ×(breadth × height + length × height)

Or, y = 2 ×(b × h + l × h)

Or, 2 ×(b × h + l × h) = 63

Or, (b × h + l × h) = \dfrac{63}{2}              ......2

Putting value of eq 2 into eq 1

so,  (l × b +  \dfrac{63}{2} ) = \dfrac{95}{2}    

Or, l × b = \dfrac{95}{2} - \dfrac{63}{2}    

Or,  l × b = \dfrac{95 - 63}{2}

i.e l × b = \dfrac{32}{2}

so, l × b = 16

<u>Now, Again</u>

∵The Area of the base = ( length × breadth ) cm²

So, z =  l × b

i.e z = 16 cm²

So, The Area of the base = z = 16 cm²

Hence,The Area of the base is 16 cm² . Answer

5 0
3 years ago
The temperature went from -12°F to 18°F. How much did the temperature change
vlada-n [284]

Answer:

18 - (-12)

Step-by-step explanation:

Final temp. - Initial temp. = the change in temperature

By -12, we're indicating that is below zero (which is obvious) meaning that it is not in the "normal" scale nor in the imaginary scale of numbers. So, we can operate the following...

18 - (-12) = 30

So the temperature changed by 30 values or the temperature increased by 30 values, because the number is positive.

6 0
3 years ago
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