All categories

3 years ago

How do you do -19+C/3=8 can someone teach how to solve this problem?

1 answer:

3 0

You're looking for c, so you want to isolate it or get it by itself. To get rid of the /3 you multiply since the opposite of division is multiplication and to get rid of it, you do the opposite (like -9 you would add 9 to get it to 0). Now you are left with -19+c = 24 (the 24 is 8*3 because what you do to one side you do to the other. Now you get c by itself so you add 19 to both sides which leaves you with C= 43. Sorry if this was confusing!

You might be interested in

ANSWER AND EXPLAIN PLEASE ILL MARK BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!

rusak2 [61]

Answer:

hiii 7272<>*~_+89×[0<×<×*×

4 0

2 years ago

Anyone know the answer?

frosja888 [35]

Answer:

3/4

Step-by-step explanation:

3*3=9

3*4=12

4 0

2 years ago

Read 2 more answers

Please help no link as answers

Katarina [22]

Step-by-step explanation:

You can imagine this figure as a rectangle and cube

If you want volume of this irregular figure than you have to do it like this:

V(figure)= V(rectangle)+ V(cube)

V(figure)= a*b*c+ a³

V(figure)= 4*3*(I don't see dimension on the left)+ 3³

V(figure)=12*(I don't see dimension on the left)+ 27

And only you have to to do is to set this dimension which I can't see.

6 0

3 years ago

If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen

s344n2d4d5 [400]

From the first equation
6x - y = 1
6x - y - 1 = 0
6x - 1 = y

Substituting we get
4x - 3(6x - 1) = -11

5 0

3 years ago

Train a travel 175 miles in a four hours. for train b y=43.5x represents its rate of speed over the same 4 hours which train tra

stepan [7]

Answer:

Train A is faster by a factor of 1.01

Step-by-step explanation:

Given:

Train A:

Distance = 175 Miles

Time = 4 Hours

Train B:

y=43.5x

To Find:

which train travels at a faster rate in by what factor =?

Solution:

The speed of the train A = $\frac{Distance}{time}$

The speed of train A = $\frac{175}{4}$

The speed of train A = 43.75 miles per hour

Speed of the train B is the slope of the given line

The standard equation of the slope of the line is

y = mx+b

where m is the slope

and we are given with

y = 43.5x

So comparing with the standard equation

m = 43.5

Hence the speed of train B is 43.5 miles per hours

Train A travels faster

$Rate =\frac{\text{speed of train A}}{\text {Speed of train B}}$

$rate = \frac{43.75}{43.5}$

rate =1.01

7 0

3 years ago