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Sliva [168]
3 years ago
9

suppose your parents are helping you invest money for the future. they open an account for you in January with an initial deposi

t of $200 that is compounded monthly at a rate of 3.6%. from now on, at the end of each month, you will deposit $200. how much money will be in your account at the end of the year?
Mathematics
1 answer:
alex41 [277]3 years ago
6 0
X=year
y=$

y=200(1.003)^12x

3.6%->.036/12 (compounded monthly)

=0.003+1

y=200(1.003)^12(1) (1 year)

=$207.31999

BUT

200•12 ($200 deposited every month)

=$2400

2400+207.3199=

$2607.32
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Step-by-step explanation:

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AlekseyPX

Answer:

The width of the sandbox is 42\frac{2}{3} \ ft.

Step-by-step explanation:

Given,

Area of the sandbox = 10\frac{2}{3}=\frac{32}{3}\ ft^2

Length = \frac{1}{4}\ ft

Solution,

Let the width of the sandbox be 'w'.

Since the sandbox is in shape of rectangle.

So we use the formula of area of rectangle.

Area = Length\times Width

On substituting the given values, we get;

\frac{1}{4}\times w=\frac{32}{3}\\

By cross multiplication method, we get;

w=\frac{32\times4}{3\times 1} =\frac{128}{3} =42\frac{2}{3} \ ft

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Step-by-step explanation:

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2 years ago
List P contains m numbers; list Q contains n numbers. If the two lists are combined to produce list R, containing m + n numbers,
Anarel [89]

Answer: YES

Step-by-step explanation:

We need to write out the expressions

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If 2m=n then we can say;

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It is obvious that the smaller number in Q is greater than the largest number in P

We can make some assumptions.

Let n= (x,y,z)

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3 years ago
A box contains 2 dozen pairs of contact lenses ,of which 8 pairs are tinted. A pair of contact lenses is drawn at random from th
tia_tia [17]

Answer:

\dfrac{2}{3}.

Step-by-step explanation:

It is given that a box contains 2 dozen pairs of contact lenses ,of which 8 pairs are tinted.

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Total pairs of contact lenses =2\times 12 = 24

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If a pair of contact lenses is drawn at random from the box, then we need to find the probability that it is not tinted.

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Therefore, the required probability is \dfrac{2}{3}.

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3 years ago
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