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Fittoniya [83]
3 years ago
10

The table shows a function. x 5  4  3  2  1  0 1 2 3   fx 11  3  5 13 21 29 37 45 53 (a) Is the function linear, expone

ntial, or neither? (b) What is the pattern that you observe in the table ? (for example: adding 5 each time x increases by 1, dividing by 2 each time x increases by 3) If there is no pattern, show that there is no pattern. (c) W hat is the y - intercept of the function represented by the table? (be sure to write as an ordered pair)
Mathematics
1 answer:
Andreyy893 years ago
7 0

Answer:

We have been given a table:

x: -5  -4  -3  -2  -1  0  1  2  3

f(x):-11  -3  5  13  21  29  37  45  53

Part (a) the function is linear the line is a straight line from two points given above

Function is: y+11=8(x+5)  from point (-5,-11)

                   y=8x+29

Part (b) adding 8 each time x increases by 1

Part (c) the function is y =8x+29

To find y-intercept put x =0 we get y=29

So, y-intercept is (0,29).

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Answer:

\sqrt{55}

Step-by-step explanation:

Based off of what we do know, if we can find length DB we can use the pythagorous theorem (I will be assigning the variable z)

x^{2} =36+z^{2} \\\\y^{2}=25+z^2\\\\x^{2} +y^2=121\\\\

First equation is for triangle ABD

Second is for BCD

And the last one is for ACD

Substitute x^{2} and y^2

36+z^2+25+z^2=121\\\\61+2z^2=121\\\\2z^2=60\\\\z^2=30\\\\z=\sqrt{30}

As discovered before

y^2=25+z^2\\\\y^2=25+30\\\\y^2=55\\\\y=\sqrt{55}

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