If Jack has 15 pencils and Jill has seven pencils what is the difference between Jack and Jill

If the income of a person is Rs 18,000 per month , the exemption of the income is Rs 1,40,000 per year, If he has paid Rs 11,400 as an income tax at the end of the year . The percent per annum of the tax paid is: 15%.

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</h3><h3>Tax percentage</h3>

Given:

Income of a person=Rs 18,000 per month

Exemption income per year=140,000

Income tax paid=11,400

First step is to the calculate the Income per year since the income of a person is Rs 18,000 per month

Income per year= 18,000 ×12

Income per year=216,000

Second step is to calculate the taxable income

Taxable income=216,000-140,000

Taxable income=76,000

Third step is to calculate the tax Percentage per annum

Tax percentage=11,400/76,000×100

Tax percentage=15%

Therefore If he has paid Rs 11,400 as an income tax at the end of the year . The percent per annum of the tax paid is: 15%.

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7 0

1 year ago

What is the sum of (–6) + (–6) + (–6) + (–6) + (–6) + (–6)

nalin [4]

It looks like you've got six numbers lined up there, every one of them is the same number, and you need to have them added up.

Well, you've got (-6) listed six ==> <em>TIMES</em> <== , so the situation is the same as if you just wrote

6 x (-6)

and that's just <em>-36 </em>.

5 0

3 years ago

Read 2 more answers

Xsquared+1/20x-1/20 so I need that to be solved any way possible

VARVARA [1.3K]

Hallo ^_^

Quadratic Equation :
ax² + bx + c = 0

From the task :
x² + 1/20 x = 1/20

Switch sides :
x² + 1/20x - 1/20 = 0

Multiple each sides by 20
20(x² + 1/20x - 1/20) = 0(20)
⇒ 20x² + x - 1 = 0

From that :
a = 20, b = 1 and c = - 1

Solve x using quadratic formula :

$x_1x_2 = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Substitution using the formula :

$x_1x_2 = \frac{-1 \pm \sqrt{1^2-4(20)(-1)}}{2(20)} \\\\
x_1x_2 = \frac{-1 \pm \sqrt{81}}{40} \\\\
x_1x_2 = \frac{-1 \pm 9}{40} \\\\

x_1 = \frac{- 1 + 9}{40} \\\\
x_1 = \frac{8}{40} \\\\
x_1 = \frac{1}{5} \\\\

x_2 = \frac{- 1 - 9}{40} \\\\
x_2 = \frac{-10}{40} \\\\
x_2 = - \frac{1}{4} \\\\

\therefore \boxed{x = \frac{1}{5} \ or \ x =- \frac{1}{4}}$

Sorry for my bad english :)

5 0

2 years ago