The problem uses the perimeter formula. P = 2w + 2l where w is the width, and l is the length.
We know the length (l) is 3 inches longer than it's width (or l = w+3). Substitute w +3 into Perimeter equation
P = 2w + 2(w+3). That simplifies to P = 4w + 6.
Since P + 42, we have 42 = 4w +6. With some simple algebra we find that w = 9 and l = 12.
Hope this helps!
Answer:
84 units
Explanation:
If B is the midpoint of line AC, then B divides AC into two equal parts (AB and BC).
Therefore:
AB=BC
2x-8=x+17
2x-x=17+8
x=25
Therefore, the measure of the line segment AC
=2(2x-8)
=2(2(25)-8)
=2(50-8)
=2(42)
AC=84 units
(2) + (2)
=> 8x - 6y = -46 ———(3)
(1) + (3)
=> 5x + 6y + (8x - 6y) = 20 - 46
=> 13x + (6-6)y = -26
=> 13x + 0y = -26
=> 13x = -26
=> x = -26/13
=> x = -2
=> 5(-2) + 6y = 20
=> 6y = 20 + 10
=> 6y = 30
=> y = 5
x = -2, y = 5 => C
To the hundredth place, or second decimal this would be 1.004_
So this will become 1.0
-3 • (5x + 2y = 7)
-15x - 6y = -21
-2x + 6y = 9
__________
-17x = -12
x = 12/17
5(12/17) + 2y = 7
2y = 7 - 60/17
2y = 3.47
y = 1.735
