The second choice is the answer: the initial value is the y value (which is 4) and the rate of change is the slope. The slope is calculated with rise/run, so the rise in this situation is that it moves down (negative) by 3 (rise=-3) and the run is how much it moves to the right (run=4). Therefore, the rate of change is rise/run which is -3/4
The question is incomplete. The complete question is :
The population of a certain town was 10,000 in 1990. The rate of change of a population, measured in hundreds of people per year, is modeled by P prime of t equals two-hundred times e to the 0.02t power, where t is measured in years since 1990. Discuss the meaning of the integral from zero to twenty of P prime of t, d t. Calculate the change in population between 1995 and 2000. Do we have enough information to calculate the population in 2020? If so, what is the population in 2020?
Solution :
According to the question,
The rate of change of population is given as :
in 1990.
Now integrating,

![$=\frac{200}{0.02}\left[e^{0.02(20)}-1\right]$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B200%7D%7B0.02%7D%5Cleft%5Be%5E%7B0.02%2820%29%7D-1%5Cright%5D%24)
![$=10,000[e^{0.4}-1]$](https://tex.z-dn.net/?f=%24%3D10%2C000%5Be%5E%7B0.4%7D-1%5D%24)
![$=10,000[0.49]$](https://tex.z-dn.net/?f=%24%3D10%2C000%5B0.49%5D%24)
=4900





This is initial population.
k is change in population.
So in 1995,



In 2000,


Therefore, the change in the population between 1995 and 2000 = 1,163.
Answer:
1. V={π(3^2)*9 in^3}/3=84.82 in^3
2. V= {π(7^2)*11 in^3}/3=564.44 in^3
3. V= {π(15^2)*20 in^3}/3=4,712.39 yd^3
Step-by-step explanation:
V=π(r^2)h
Answer: x=6
Step-by-step explanation: