means to say that for any given 
, we can find 
such that anytime 
(i.e. the whenever 
is "close enough" to 5), we can guarantee that 
(i.e. the value of 
is "close enough" to the limit value).
What we want to end up with is
Dividing both sides by 3 gives
which suggests 
is a sufficient threshold.
The proof itself is essentially the reverse of this analysis: Let be given. Then if
and so the limit is 7. QED
Step 1
distribute the -3
-3(y-5)=24
-3y+15=24
step 2
subtract 15 from both sides
-3y =9
Step 3
divide -3 on both sides
y=-3
It’s 102in sorry if I’m late to answer
Answer:
markup=62 %
Step-by-step explanation:
It 10,000,000 because there is no way that it can be in expanded form
