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3 years ago

487/8 plsssssssssssss

Mathematics

2 answers:

Helga [31]3 years ago

6 0

that would be 60.875

also there is such thing as a calculator

Vesnalui [34]3 years ago

5 0

60.875 is the answer you need.

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I believe the answer is B can anyone confirm please?

Marizza181 [45]

The answer is D, not B

7 0

4 years ago

What are the potential solutions of log4x+log4(x+6)=2?

lions [1.4K]

The potential solutions of $log_4x+log_4(x+6)=2$ are 2 and -8.

<h3>Properties of Logarithms</h3>

From the properties of logarithms, you can rewrite logarithmic expressions.

The main properties are:

Product Rule for Logarithms - $log_{b}(a*c)=log_{b}a+log_{b}c$
Quotient Rule for Logarithms - $log_{b}(\frac{a}{c} )=log_{b}a-log_{b}c$
Power Rule for Logarithms - $log_{b}(a^c)=c*log_{b}a$

The exercise asks the potential solutions for $log_4x+log_4(x+6)=2$ . In this expression you can apply the Product Rule for Logarithms.

$log_4x+log_4(x+6)=2\\ \\ x*(x+6)=4^2\\ \\ x^2+6x=16\\ \\ x^2+6x-16=0$

Now you should solve the quadratic equation.

Δ= $b^2-4ac=36-4*1*(-16)=36+64=100$ . Thus, x will be $x_{1,\:2}=\frac{-6\pm \:\sqrt{100} }{2\cdot \:1}=\frac{-6\pm \:10}{2}$ . Then:

$x_1=\frac{-6+10}{2}=\frac{4}{2} =2\\ \\ \:x_2=\frac{-6-10}{2}=\frac{-16}{2} =-8$

The potential solutions are 2 and -8.

Read more about the properties of logarithms here:

brainly.com/question/14868849

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2 years ago

Graph the equation y=-4/3x + 2

vaieri [72.5K]

Answer:

plz if you knew if you new it plz tell me

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3 years ago

Help snsnsnansnsnsnsns

N76 [4]

Answer:

answer is 420-69

Step-by-step explanation:

because those numbers are great

8 0

3 years ago

Find the midpoint of the segment with the given endpoints. (-10.2) and (0,-7)

iris [78.8K]

Answer:

$=\left(-5,\:-\frac{5}{2}\right)$

Step-by-step explanation:

$\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)\\\\\left(x_1,\:y_1\right)=\left(-10,\:2\right),\:\left(x_2,\:y_2\right)=\left(0,\:-7\right)\\\\=\left(\frac{0-10}{2},\:\frac{-7+2}{2}\right)\\\\= (\frac{-10}{2} , \frac{-5}{2})\\ \\=\left(-5,\:-\frac{5}{2}\right)$

7 0

3 years ago