Where are the variables for the equation?
If the parabola has y = -4 at both x = 2 and x = 3, then since a parabola is symmetric, its axis of symmetry must be between x = 2 and x = 3, or at x = 5/2. Our general equation can then be:
y = a(x - 5/2)^2 + k
Substitute (1, -2): -2 = a(-3/2)^2 + k
-2 = 9a/4 + k
Substitute (2, -4): -4 = a(-1/2)^2 + k
-4 = a/4 + k
Subtracting: 2 = 2a, so a = 1. Substituting back gives k = -17/4.
So the equation is y = (x - 5/2)^2 - 17/4
Expanding: y = x^2 - 5x + 25/4 - 17/4
y = x^2 - 5x + 2 (This is the standard form.)
The remainder from the division of the algebraic equation is -53/8.
<h3>What is the remainder of the algebraic expression?</h3>
The remainder of the algebraic expression can be determined by using the long division method.
Given that:
where:
Using the long division method, we have:
Therefore, we can conclude that the remainder is -53/8.
Learn more about the division of algebraic equations here:
brainly.com/question/4541471
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Answer: x = 13/5
Explanation:
(x+4)/(3x+1) = 3/4
Cross multiply:
4(x+4) = 3(3x+1)
4x + 16 = 9x + 3
4x - 9x = 3 - 16
-5x = -13
x = -13/-5
x = 13/5
The slope intercept is equal to the rise/run.
So lets say to get from one point to the other, you go down 2 units and go right 3 units.
Since you went down it is a -2. If you had gone up 2 units, then it would be a positive 2.
Since you went to the right, it is a positive 3. If you had gone left 3 units, then it would be -3.
-2/3
