1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aalyn [17]
3 years ago
13

Alyssa purchased a house for 243,000 and obtained a mortgage for 231,000. she purchased 5 discount points and 4 origination poin

ts. what is the cost for each?
Mathematics
1 answer:
vivado [14]3 years ago
8 0
It should be noted that:

1 point = 1% = 0.01

Therefore,
Cost of points = Number of points*0.01*Mortgage

Substituting;
Cost of discount points = 5*0.01*231,000 = $11,550
Cost of originating points = 4*0.01*231,000 = $9,240
You might be interested in
Rewrite the following in the form log(c).<br> log(10) – log(5)
Svet_ta [14]

Answer:

log(2)

Step-by-step explanation:

In order to combine log(10) and log(5), you need to look at the sign that's combining them. In this example, it is a subtraction sign. When two logs are being subtracting from each other, it's the same as dividing the two. You would rewrite it like this:

log(10/5)

You would then solve 10/5, and get 2. You would rewrite the log as:

log(2)

3 0
2 years ago
Three forces act on a hook. Determine the magnitude of the resultant of the force.
Novay_Z [31]

Use Hooke's law... (just kidding)

Break down each force vector into horizontal and vertical components.

\vec F_1=(1000\,\mathrm N)(\cos30^\circ\,\vec x+\sin30^\circ\,\vec y)\approx(866.025\,\mathrm N)\,\vec x+(500\,\mathrm N)\,\vec y

\vec F_2=(1500\,\mathrm N)(\cos160^\circ\,\vec x+\sin160^\circ\,\vec y)\approx(-1409.54\,\mathrm N)\,\vec x+(513.03\,\mathrm N)\,\vec y

\vec F_3=(750\,\mathrm N)(\cos195^\circ\,\vec x+\sin195^\circ\,\vec y)\approx(-724.444\,\mathrm N)\,\vec x+(-194.114\,\mathrm N)\,\vec y

The resultant force is the sum of these vectors,

\vec F=\displaystyle\sum_{i=1}^3\vec F_i\approx(-1267.96\,\mathrm N)\,\vec x+(818.916\,\mathrm N)\,\vec y

and has magnitude

|\vec F|\approx\sqrt{(-1267.96\,\mathrm N)^2+(818.916\,\mathrm N)^2}\approx1509.42\,\mathrm N

The closest answer is D.

5 0
2 years ago
Please help!<br> And explain the answers too!
RideAnS [48]
1) He worked 4 hours leaving 6 more hours for him.
rate for A alone 6 baker
rate for A & B together 4
1/a+1/b=1/x
1/6+1/b=1/4
1/b=1/4-1/6
1/b=6/24-4/24
1/b=2/24
1/b=1/12
b=12
rate for wife alone 12 hours for the remaining 6 hours
check
1/6+1/12=1/4
12/72+6/72=1/4
18/72=1/4
ok
codewa
But we want to know how long it would have taken her for the whole job not just part of it
he works twice as fast as she does so the job that takes him 10 hours alone would take her 20 hours alone.

2) jessica and cynthia work in a pet shop.
it takes jessica 6 hours to groom all the pets but cynthia needs 8 hours to groom them.
if jessica starts to groom 1 hour before cynthia joins, how long will it take them to finish?
:
let t = time it takes them to finish (C's working time)
then
t+1 = J's working time
let 1 = completed job (all pets groomed)
:
A shared work equation, each does a fraction of the job, the two fractions add up to 1
%28%28t%2B1%29%29%2F6 + t%2F8 = 1
Multiply by the least common multiple of 6 and 8, 24. cancel the denominators
4(t+1) + 3t = 24
4t + 4 + 3t = 24
4t + 3t = 24 - 4
7t = 20
t = 20/7
t = 26%2F7 hrs, which is: 2 + 6%2F7*60 = 2 hrs 51.43 min to finish the job

3) math club takes 40 minutes
science takes 50 minutes.
rate * time = quantity
quantity = 1 set up of the tables.
rate for math club is 1/40 of all the tables in 1 minute.
rate for science club is 1/50 of all the tables in 1 minute.
math club works for 10 minutes.
rate * time = quantity
1/40 * 10 = 10/40 = 1/4 of the tables are already set up by the math club.
there are 3/4 of the tables that still need to be set up.
rate * time = quantity
the rates of the math club and the science club are additive.
(1/40 + 1/50) * time = 3/4 of the tables that still need to be set up.
common denominator is 200.
(5/200 + 4/200) * time = 3/4.
9/200 * time = 3/4
time = 3/4 * 200/9 = 600 / 36 = 16 and 2/3 minutes.
total time required is 10 + 16 + 2/3 minutes = 26 + 2/3 minutes.
how to check.
10 minutes is used to do 1/4 of the tables.
16 + 2/3 minutes is used to do the remaining 3/4 of the tables.
combined rate of math and science club is 9/200 of the tables in 1 minute.
math club rate of 1/40 * 10 = 10/40 = 1/4 of the tables.
combine rate of 9/200 * (16 + 2/3) = 9/200 * 50/3 = 450/600 = 9/12 = 3/4 of the tables.
1/4 + 3/4 = 1 = all of the tables.

6 0
2 years ago
F(x)=x2-10x+16 how do I solve that ​
Vsevolod [243]

Step-by-step explanation:

3373eoeenejdidheidndjdjdjjd

7 0
3 years ago
Estimate then record the product 293*4
jolli1 [7]

I believe that the equations answer is around 1170. The answer to the equation is 1172

3 0
3 years ago
Other questions:
  • Organize the following expressions from greatest to least by number of terms:
    6·2 answers
  • An athletic field is a 42 yd​-by-84 yd ​rectangle, with a semicircle at each of the short sides. A running track 20 yd wide surr
    9·1 answer
  • Help me with this question
    10·1 answer
  • Order the values from least to greatest. -21/2 -1/2, |1/2|, 1 1/2, |-2|, |-2 1/2|​
    12·1 answer
  • Someone pls help, i will give brainliest
    7·1 answer
  • Cheryl kept track of the changes in temperature one night. At 7:00 P.M. the
    15·1 answer
  • Please help. Cleary show what the slope and y-intercept are for each problem. An explanation would be nice, but I'm not going to
    13·1 answer
  • mike and sam are running laps. mike runs a lap in 5 minutes and sam runs a lap in 6 minutes. if mile and sam begin running at th
    15·1 answer
  • 11 is 0.6 percent of what number
    14·1 answer
  • 4.678<br> written to one decimal point would be​
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!