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almond37 [142]
4 years ago
8

Whats the reciprocal for 1 1/14 pls help-​

Mathematics
2 answers:
Oksana_A [137]4 years ago
8 0
14/15 (if i am understanding this correctly)
mezya [45]4 years ago
5 0

Answer:

14/15

Step-by-step explanation:

1 1/14

=> 14 x 1 + 1/14

=> 15/14

Reciprocal = Opposite

=> 15/14 reciprocal = 14/15

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The formula for glue says to add 60 mL of hardener to each container of resin. How much hardener should be added to 19 container
Inessa05 [86]
60 mL = 60/1000 L
= 0.06 L
1 container of resin = 0.06L
19 containers of resin = 0.06 x 19
= 1.14 L

1.14 L of hardener should be added to 19 containers of resin.
4 0
4 years ago
HELP!!!
xz_007 [3.2K]

Step-by-step explanation:

Given that the graph shows the normal distribution of the length of similar components produced by a company with a mean of 5 centimeters and a standard deviation of 0.02 centimeters.

A component is chosen at random, the probability that the length of this component is between 4.98 centimeters and 5.02

=P(|z|<1) (since 1 std dev on either side of the mean)

=2(0.3418)

=0.6826

=68.26%

The probability that the length of this component is between 5.02 centimeters and 5.04 centimeters is

=P(1<z<2) (since between 1 and 2 std dev from the mean)

=0.475-0.3418

=0.3332

=33.32%

6 0
4 years ago
Read 2 more answers
Ugh lol help please​
seropon [69]

Answer:

I think it might be D but feel free to correct me if I'm wrong

5 0
3 years ago
Put the following equation into slope intercept form: 5x – 3y = -9.
Minchanka [31]

y = \frac{5}{3} x + 3 → B

subtract 5x from both sides

- 3y = - 5x - 9 ( multiply through by ( - 1 ) )

3y = 5x + 9 ( divide all terms by 3 )

y = \frac{5}{3} x + 3 ( in slope- intercept form )


5 0
4 years ago
Find the point(x,y) on the graph of y=√x nearest the point(4,0)
Nata [24]
F(x)=sqrt(x)
D(x)=sqrt((f(x)-0)^2+(x-4)^2)  [distance of (4,0) from any point on graph]
=sqrt((&radic;x-0)^2+(x-4)^2)
=sqrt(x+(x-4)^2)
To minimize distance, we equate D'(x)=0, or equivalently, we equate the derivative of D(x)^2 to zero.
The latter is easier to derive, and gives the same results.
We will do both.
D'(x)=(1/2)(2(x-4)+1)/sqrt(x+(x-4)^2)   [using chain rule]
D'(x)=0 => (2(x-4)+1)=0 => x-4=-1/2 => x=7/2

d(D&sup2;(x))/dx
=d(x+(x-4)^2)/dx
=2(x-4)+1
=> 2(x-4)+1=0  => x=7/2
So the point on the graph is (sqrt(7/2),7/2)=(1.8708,3.5)  approx.
8 0
3 years ago
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