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3 years ago

HELP!!!

Mathematics

2 answers:

xz_007 [3.2K]3 years ago

6 0

Step-by-step explanation:

Given that the graph shows the normal distribution of the length of similar components produced by a company with a mean of 5 centimeters and a standard deviation of 0.02 centimeters.

A component is chosen at random, the probability that the length of this component is between 4.98 centimeters and 5.02

=P(|z|<1) (since 1 std dev on either side of the mean)

=2(0.3418)

=0.6826

=68.26%

The probability that the length of this component is between 5.02 centimeters and 5.04 centimeters is

=P(1<z<2) (since between 1 and 2 std dev from the mean)

=0.475-0.3418

=0.3332

=33.32%

Yanka [14]3 years ago

5 0

Answer:

1) 68.3%

2)33.3%

Step-by-step explanation:

Given:

mean, x= 5 cm

Standard deviation, sd= 0.02 cm

probability that the length of this component is between 4.98 centimeters and 5.02 centimeters=?

probability that the length of this component is between 5.02 centimeters and 5.04 centimeters is =?

As the graph shows the normal distribution

a component is chosen at random, the probability that the length of this component is between 4.98 centimeters and 5.02 centimeters is about:

1 sd on either side of the mean on normal distributed graph means

P(|z|<1)

=2(0.3418)

=0.683

=68.3%

the probability that the length of this component is between 5.02 centimeters and 5.04 centimeters is about:

=P(1<z<2) (since between 1 and 2 std dev from the mean)

between 1 and 2 sd on either side of the mean on normal distributed graph means

P(1<z<2)

=0.47-0.342

=0.333

=33.3%!

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Mashcka [7]

Answer:

Step-by-step explanation:

To calculate ;

1) the expected value of the job satisfaction score for senior executives ;

expected value = Summation (Px)

= 1 x 0.05 + 2 x 0.09 + 3 x 0.03 + 4 x 0.42 + 5 x 0.41

= 4.05

2) the expected value of the job satisfaction score for middle managers;

= 1 x 0.04 + 2 x 0.10 + 3 x 0.12 + 4 x 0.46 + 5 x 0.28

= 3.84

c) the variance of job satisfaction scores for executives and middle managers (to 2 decimals).

Executives ; Variance = Summation(PX^2 - Summation(PX)^2

i) For Executive Managers = 1 x 0.05 + 2^2 x 0.09 + 3^2 x 0.03 + 4^2 x 0.42 + 5^2 x 0.41 - 4.05^2 = 1.246 = 1.25

ii) for middle managers ; 1 x 0.04 + 2^2 x 0.10 + 3^2 x 0.12 + 4^2 x 0.46 + 5^2 x 0.28 - 3.84^2 = 1.134 = 1.13

d) the standard deviation of job satisfaction scores for both probability distributions (to 2 decimals). Executives, Middle managers;

For Executives = square root [ 1 x 0.05 + 2^2 x 0.09 + 3^2 x 0.03 + 4^2 x 0.42 + 5^2 x 0.41 - 4.05^2] = 1.12

For Middle Managers ; Square root [1 x 0.04 + 2^2 x 0.10 + 3^2 x 0.12 + 4^2 x 0.46 + 5^2 x 0.28 - 3.84^2 ] = 1.06

e) from the values gotten for the variance of both executive and middle managers, the variance of the former is more than that of the latter as such higher satisfaction with the executive managers.

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3 years ago

What is the answer to 4x-5x+9=5x-9?

fiasKO [112]

Answer:

x=3

Step-by-step explanation:

First, combine like terms on the left side

4x-5x+9=5x-9

-x+9=5x-9

Subtract 9 on both sides

-x=5x-18

Subtract 5x on both sides

-6x= -18

Divide by -6 on both sides

x=3

Hope this helps! :)

5 0

3 years ago

Read 2 more answers

Which of the following equations is true?

Korolek [52]

Answer:

Step-by-step explanation:

10×1=10

0+10=10

Hence they're equal

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2 years ago

When Alice spends the day with the babysitter, there is a 0.6 probability that she turns on the TV and watches a show. Her littl

slava [35]

Answer:

a) There is a 48% probability that both Alice and Betty watch TV tomorrow.

b) There is a 48% probability that Betty watches TV tomorrow.

c) There is a 12% probability that only Alice watches TV tomorrow.

Step-by-step explanation:

We have these following probabilities:

A 60% probability that Alice watches TV.

If Alice watches TV, an 80% probability Betty watches TV.

If Alice does not watch TV, a 0% probability that Betty watches TV, since she cannot turn the TV on by herself.

a) What is the probability that both Alice and Betty watch TV tomorrow?

Alice watches 60% of the time. Betty watches in 80% of the time Alice watches. So:

$P = 0.6*0.8 = 0.48$

There is a 48% probability that both Alice and Betty watch TV tomorrow.

b) What is the probability that Betty watches TV tomorrow?

Since Betty only watches when Alice watches(80% of the time), this probability is the same as the probability of both of them watching. So

$P = 0.6*0.8 = 0.48$

There is a 48% probability that Betty watches TV tomorrow.

c) What is the probability that only Alice watches TV tomorrow?

There is a 60% probability that Alice watches TV tomorrow. If she watches, there is an 80% probability that Betty watches and a 20% probability she does not watch.

$P = 0.6*0.2 = 0.12$

There is a 12% probability that only Alice watches TV tomorrow.

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3 years ago

No I need 54 inches of wood to build a picture frame. if the wood cost $2.50 a foot, how much will be pay?

tamaranim1 [39]

Answer:

135

Step-by-step explanation:

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3 years ago