Find the midpoint of the segment with the following endpoints. (4, -10) and (0,0)
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
You have 3 unknowns: a, b, and c. It's our job to find them algebraically. I'm going to start with the point where x = 0 and y = 7. You'll see why in a minute. Filling in the standard form of a quadratic
using (0, 7):
gives you that c = 7. We will use that value now when we write the next 2 equations. Now the point (-2, 19):
and
so
12 = 4a - 2b
Now for the next point (-1, 12):
and
so
5 = a - b
Now we have a system of equations (the 2 bold font equations) that we will solve by elimination:
12 = 4a - 2b
5 = a - b
Multiply the bottom equation by -4 to get a new system:
12 = 4a - 2b
-20 = -4a + 4b
Add those together to get rid of the a terms and end up with
-8 = 2b so
b = -4
Now we can sub in -4 for b to solve for a. I'm using the second bold type equation to do this:
5 = a - (-4) and
5 = a + 4 so
a = 1 and the equation for the quadratic function is
The variance for the data is 17,507. 5.
Given
The weekly salaries of a sample of employees at the local bank are given in the table below.
Employee Weekly Salary Anja $245 Raz $300 Natalie $325 Mic $465 Paul $100.
<h3>Variance</h3>Variance is the expected value of the squared variation of a random variable from its mean value, in probability and statistics.
The mean value of the salaries of employees is;
The variance is given by;
Hence, the variance for the data is 17,507. 5.
To know more about variance click the link given below.
Answer:
There is a 12.13% probability that the person actually does have cancer.
Step-by-step explanation:
We have these following probabilities.
A 0.9% probability of a person having cancer
A 99.1% probability of a person not having cancer.
If a person has cancer, she has a 91% probability of being diagnosticated.
If a person does not have cancer, she has a 6% probability of being diagnosticated.
The question can be formulated as the following problem:
What is the probability of B happening, knowing that A has happened.
It can be calculated by the following formula
Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.
In this problem we have the following question
What is the probability that the person has cancer, given that she was diagnosticated?
So
P(B) is the probability of the person having cancer, so
P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So
P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So
What is the probability that the person actually does have cancer?
There is a 12.13% probability that the person actually does have cancer.