Answer:
1.16
Step-by-step explanation:
Given that;
For some positive value of Z, the probability that a standardized normal variable is between 0 and Z is 0.3770.
This implies that:
P(0<Z<z) = 0.3770
P(Z < z)-P(Z < 0) = 0.3770
P(Z < z) = 0.3770 + P(Z < 0)
From the standard normal tables , P(Z < 0) =0.5
P(Z < z) = 0.3770 + 0.5
P(Z < z) = 0.877
SO to determine the value of z for which it is equal to 0.877, we look at the
table of standard normal distribution and locate the probability value of 0.8770. we advance to the left until the first column is reached, we see that the value was 1.1. similarly, we did the same in the upward direction until the top row is reached, the value was 0.06. The intersection of the row and column values gives the area to the two tail of z. (i.e 1.1 + 0.06 =1.16)
therefore, P(Z ≤ 1.16 ) = 0.877
I don’t have the time for my birthday but I’m just asking for a little
Step-by-step explanation:
Hey there!
While factorising you remember to make it take common in most of the expression.
Here;
=mx+cx+my+cy
Take common 'x' in "mx+cx" and 'y' in my + cy.
= x(m+c) + y(m+c)
Now, "(m+c)" common again.
= (m+c) (x+y)
Therefore the factorized form of the expression in (m+c)(x+y).
<u>Hope it helps</u><u>.</u><u>.</u><u>.</u>
Rewriting the left hand side,
csc²t - cost sec t
= (1/sin²t)-(cost)(1/cost)
= 1/sin²t - 1
= 1/sin²t - sin²t/sin²t
= (1-sin²t)/sin²t
= cos²t/sin²t
= cot²t
