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mr_godi [17]
4 years ago
13

PLEASE HELPP!!!! I WILL MARK BRAINLIEST!!!!!! The question is in the picture!

Mathematics
1 answer:
artcher [175]4 years ago
3 0

Answer:

Your answer is the 1st option.

Step-by-step explanation:

Either the IQR or the range are good measures of variability because the distribution has no outliers. Hope this helps

  • (\) QueTooOfficial (/)
  • <em>officially out of brainly retirement</em>
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72 inches but converted to yards
Maksim231197 [3]

Answer:

2 yards

Step-by-step explanation:

12 inches=1  ft

72 inches=1/12×72=6 ft

3 ft=1 yard

6 ft=1/3×6=2 yards

4 0
4 years ago
Read 2 more answers
sylvie needs $110 for a concert ticket. she already has $ 16 and she can earn the rest by working 10 hours at her job. if h repr
n200080 [17]

Given, Sylvie needs $110 for a concert ticket.

Sylvie has $16.

Her hourly earnings = $h

Sylvie is working 10 hours at her job.

She is getting in 1 hour = $h

So, 10 hours she will get = $ = $

So the total amount she has now = $16 + $(10h) = $()

So we can write the equation as,

110=16+10h

We can move 16 to the left side also. 16 is added to the right side. We can move it by using reverse operation of addition. Reverse operation of addition is subtraction. So we will subtract 16 from both sides. Subtracting 16 we will get,

110-16=16+10h-16

110-16=10h

We have got the required answer.

To find Sylvie's hourly income the correct options are option A and option D.

4 0
3 years ago
Read 2 more answers
Suppose it is known that 8 out of the 20 teams in the sample had a season winning percentage better than 0.500.
Ganezh [65]

Answer:

The 95% confidence interval for the true proportion of all teams that had a season winning percentage better than 0.500 is (0.1853, 0.6147).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

8 out of the 20 teams in the sample had a season winning percentage better than 0.500. This means that n = 20, \pi = \frac{8}{20} = 0.4.

95% confidence interval

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 - 1.96\sqrt{\frac{0.6*0.4}{20}} = 0.1853

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 + 1.96\sqrt{\frac{0.6*0.4}{20}} = 0.6147

The 95% confidence interval for the true proportion of all teams that had a season winning percentage better than 0.500 is (0.1853, 0.6147).

3 0
4 years ago
Factor ab + bc + b2 + ac.
Alona [7]
<span>ab + bc + b</span>²<span> + ac = 
(b</span>² + bc<span>)+(ab + ac) = 
b(b+ c)+a(b + с) = 
(b + c)(b + a)</span>
5 0
3 years ago
Read 2 more answers
(x4–3x2+1) divided by<br> (x-1)
fiasKO [112]
(X4-3x2+1) / X - 1

3x / X - 1

Hope it helps
:)
3 0
3 years ago
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