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3 years ago

How to simplify (-8r6s3)3÷r

1 answer:

3 0

Step 1. Simplify $8r*6s*3$ to $144rs$

$-144rs* \frac{3}{r}$

Step 2. Simplify $144rs* \frac{3}{r}$ to $\frac{432rs}{r}$

$- \frac{432rs}{r}$

Step 3. Cancel $r$

$-432s$

Done! :) Your answer is $-432s$

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Please answer C: <3!

Rzqust [24]

Answer:

B. subtract 8

Step-by-step explanation:

because in PEMDAS subtract is last

6 0

3 years ago

Read 2 more answers

Which two of the prime numbers below are factors of 247. a.11 b.13 c.17 d.19

guapka [62]

a) 247 ÷ 11 = 22 r.5 since there is a remainder it is not a factor

b) 247 ÷ 13 = 19 there is no remainder so this is a factor! The other factor is 19.

Answer: B, D

8 0

3 years ago

Canine Crunchies Inc. (CCI) sells bags of dog food to warehouse clubs. CCI uses an automatic filling process to fill the bags. W

KatRina [158]

Answer:

a) 0.9999 = 99.99% probability that a filled bag will weigh less than 49.5 kilograms

b) 0.0018 = 0.18% probability that a randomly sampled filled bag will weight between 48.5 and 51 kilograms.

c) 46.24 kilograms

d) The standard deviation would have to be of 3.41 kilograms.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 45 kilograms and a standard deviation of 1.2 kilograms.

This means that $\mu = 45, \sigma = 1.2$

a. What is the probability that a filled bag will weigh less than 49.5 kilograms?

This is the pvalue of Z when X = 49.5. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{49.5 - 45}{1.2}$

$Z = 3.75$

$Z = 3.75$ has a pvalue of 0.9999

0.9999 = 99.99% probability that a filled bag will weigh less than 49.5 kilograms

b. What is the probability that a randomly sampled filled bag will weight between 48.5 and 51 kilograms?

This is the pvalue of Z when X = 51 subtracted by the pvalue of Z when X = 48.5.

X = 51

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{51 - 45}{1.2}$

$Z = 5$

$Z = 5$ has a pvalue of 1

X = 48.5

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{48.5 - 45}{1.2}$

$Z = 2.92$

$Z = 2.92$ has a pvalue of 0.9982

1 - 0.9982 = 0.0018

0.0018 = 0.18% probability that a randomly sampled filled bag will weight between 48.5 and 51 kilograms.

c. What is the minimum weight a bag of dog food could be and remain in the top 15% of all bags filled?

This is the 100 - 15 = 85th percentile, which is X when Z has a pvalue of 0.85. So X when Z = 1.037

$Z = \frac{X - \mu}{\sigma}$

$1.037 = \frac{X - 45}{1.2}$

$X - 45 = 1.037*1.2$

$X = 46.24$

46.24 kilograms.

d. CCI is unable to adjust the mean of the filling process. However, it is able to adjust the standard deviation of the filling process. What would the standard deviation need to be so that no more than 2% of all filled bags weigh more than 52 kilograms?

X = 52 would have to be the 100 - 2 = 98th percentile, which is X when Z has a pvalue of 0.98, so X when Z = 2.054. We would need to find the value of $\sigma$ for this.

$Z = \frac{X - \mu}{\sigma}$

$2.054 = \frac{52 - 45}{\sigma}$

$2.054\sigma = 7$

$\sigma = \frac{7}{2.054}$

$\sigma = 3.41$

The standard deviation would have to be of 3.41 kilograms.

5 0

3 years ago

From the expressions below, select the one that results in a negative difference.

balu736 [363]

uhm..

what expressions?

5 0

3 years ago

Certain kinds of goods tend to have inelastic demand; a good usually has inelastic demand if what?

hichkok12 [17]

Usually if it's an basic good, or very important one.

because the price fluctuations do not affect the quantity sold.

a good example of that would be milk, if the milk gallon is say $8, and a family needs 1 gallon daily, they buy it for $8.

if the price drops to $7, they might buy 2, but they only need 1 everyday, just in case they may get another.

if the price drops to $4 or even $3, they're not going to get 10 gallons, there's no need for it on an everyday basis, besides is a perishable.

now if the price goes up to $12, they still need it, and will buy it for $12.

3 0

3 years ago