Answer:
y=3/4x-2
a=(8/3,0)
b=(0,-2)
m=3/4
Step-by-step explanation:
STEP 1
3x-4y =8 substract 3x from both sides
-4y=-3x+8 divide -4 to everything
y=3/4x-2
STEP 2
substitute 0 for y and solve for a (x-intercept)
Answer:
.96 or .97
Step-by-step explanation:
2a+b4.....................
Answer:


Step-by-step explanation:
Given

Solving (a): Write as inverse function

Represent a(d) as y

Swap positions of d and y

Make y the subject


Replace y with a'(d)

Prove that a(d) and a'(d) are inverse functions
and 
To do this, we prove that:

Solving for 

Substitute
for d in 




Solving for: 

Substitute 5d - 3 for d in 

Add fractions



Hence:

5^-4 / 5^3
= 5^-1
= 1/5
answer
<span>5^−1
</span><span>1 over 5</span>