The interpretation of the given question is as follows:
Use the given inverse to solve the system of equations
The inverse of ![\left[\begin{array}{ccc}1&-1&1\\0&2&1\\3&-8&0\end{array}\right] is \left[\begin{array}{ccc}-8&8&3\\-3&3&1\\6&-5&-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-1%261%5C%5C0%262%261%5C%5C3%26-8%260%5Cend%7Barray%7D%5Cright%5D%20%20%20is%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-8%268%263%5C%5C-3%263%261%5C%5C6%26-5%26-2%5Cend%7Barray%7D%5Cright%5D)
x =
y =
z =
Answer:
x = - 1.5
y = - 0.5
z = - 5
Step-by-step explanation:
Using the correlation of inverse of matrix AX = B to solve the question above;
AX = B
⇒ A⁻¹(AX) = A⁻¹ B
X = A⁻¹ B
So ;
X = A⁻¹ B
![\left[\begin{array}{c}x\\y\\z\end{array}\right] =](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D)
![\left[\begin{array}{ccc}-8&8&3\\-3&3&1\\6&-5&-2\end{array}\right] =](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-8%268%263%5C%5C-3%263%261%5C%5C6%26-5%26-2%5Cend%7Barray%7D%5Cright%5D%20%3D)
![\left[\begin{array}{ccc}-6\\ -6\\- \dfrac{1}{2}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-6%5C%5C%20-6%5C%5C-%20%5Cdfrac%7B1%7D%7B2%7D%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}(-8*-6)+(8*-6)+(3*-\dfrac{1}{2})\\(-3*-6)+(3*-6)+(1*-\dfrac{1}{2})\\(6*-6)+(5*-6)+(-2* - \dfrac{1}{2})\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%28-8%2A-6%29%2B%288%2A-6%29%2B%283%2A-%5Cdfrac%7B1%7D%7B2%7D%29%5C%5C%28-3%2A-6%29%2B%283%2A-6%29%2B%281%2A-%5Cdfrac%7B1%7D%7B2%7D%29%5C%5C%286%2A-6%29%2B%285%2A-6%29%2B%28-2%2A%20-%20%5Cdfrac%7B1%7D%7B2%7D%29%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}(48)+(-48)+(\dfrac{-3}{2})\\(18)+(-18)+(\dfrac{-1}{2})\\(-36)+(30)+(1)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%2848%29%2B%28-48%29%2B%28%5Cdfrac%7B-3%7D%7B2%7D%29%5C%5C%2818%29%2B%28-18%29%2B%28%5Cdfrac%7B-1%7D%7B2%7D%29%5C%5C%28-36%29%2B%2830%29%2B%281%29%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}(\dfrac{-3}{2})\\(\dfrac{-1}{2})\\(-5)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%28%5Cdfrac%7B-3%7D%7B2%7D%29%5C%5C%28%5Cdfrac%7B-1%7D%7B2%7D%29%5C%5C%28-5%29%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}-1.5\\-0.5\\ -5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1.5%5C%5C-0.5%5C%5C%20-5%5Cend%7Barray%7D%5Cright%5D)
Answer:
No
Step-by-step explanation:
like terms are terms which have the same variable , that is
10x and - 5x are like terms, they both have the same variable x
So for the first one... Let's just use x for months and m for minutes.
(20m)+(.15m)
20 times the number of months plus .15 times the number of minutes
Same for the next one
(35x)+ (.10m)
35 times the number of months +.10 times the minutes.
Answer:
24 Cats.
Step-by-step explanation:
You can set up an inequality of 21/18 and 28/x.
Multiply 18 and 28, you get 504. Divide 504 by 21 and you get your answer of 24.
12x is the correct answer
