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3 years ago

What are some real life geometric examples

1 answer:

Nutka1998 [239]3 years ago

4 0

Anything with a shape involves geometry

so, building houses is a big one, as you need the size and dimensions of everything to design it

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A ranger spots a forest fire on a 24-meter observation tower. The angle of depression from the tower to the fire is 29°. To the

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4.57 meters away from the fire

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3 years ago

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How can estimating be helpful?

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A restaurant charges $5.00 for a slice of pizza that is 1/3 of a pizza and $4.50 for a slice that is 1/5 of a pizza. One day the

katrin [286]

Answer:

Step-by-step explanation:

Given that:

Price of whole pizza (A) = 5 × 3 = $15
Price of whole pizza (B) = 4.50 × 5 = $22.50

They make 8 whole pizzas.

Therefore

Thirds (A) = 15 × 8 = $120
Fifths (B) = 22.50 × 8 = $180

They'll make more money if they slice it into fifths.

180 - 120 = $60

Because if they slice it into thirds, total profit will be $60 less

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#IndonesianPride - kexcvi

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2 years ago

A random sample of 9 wheels of cheese yielded the following weights in pounds has a sample mean of 20.90 and a sample variance o

Ronch [10]

Answer:

$2.002 \leq \sigma^2 \leq 11.365$

Step-by-step explanation:

1) Data given and notation

s represent the sample standard deviation

$s^2$ represent the sample variance

n=9 the sample size

Confidence=90% or 0.90

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^9 (x_i -\bar x)^2}{n-1}}
The sample variance given was [tex]s^2=3.45$

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=9-1=8$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical values.