Answer:
this answer requires that you do a little solving to find all the dimensions we need for the volume.
We know that H (height) = 2m
Diameter = 5 x height, so
Diameter = 5 x 2m = 10m
If you have the formula for finding the volume of a cylinder, it is basically the area of the circular base x cylinder height. You may know already that the area of a circle is (pi) x radius2
So this will be 2 (the height) x (pi) x r2
As we just figured out, the DIAMETER is 10, so the radius is half the diameter = 5.
This brings our volume to 2 x (pi) x 52
= 2 x (pi) x 25
2x25 = 50, so we have 50 x (pi).
Pi = 3.14
50 x 3.14 = 157
And don't forget your units = 157 m3
Answer:
C
Step-by-step explanation:
So we have the product of:
![(-6x^3y^5)\cdot(-4y^2)](https://tex.z-dn.net/?f=%28-6x%5E3y%5E5%29%5Ccdot%28-4y%5E2%29)
Multiply. Combine like terms:
![=(-6\cdot -4)(x^3)(y^5\cdot y^2)](https://tex.z-dn.net/?f=%3D%28-6%5Ccdot%20-4%29%28x%5E3%29%28y%5E5%5Ccdot%20y%5E2%29)
The first term is 24.
The second term stays as it is.
The third term will equate to y^7. Recall how to multiply exponents. The base stays constant and you add the exponents. Thus:
![=24x^3y^7](https://tex.z-dn.net/?f=%3D24x%5E3y%5E7)
Our answer is C.
And we're done!
<u>Answer with Step-by-step explanation:</u>
We are given two tables and we are to complete the missing values.
For table one, we are to substitute the given values of x in the term
:
when x = 0, ![4^{-0} = 1](https://tex.z-dn.net/?f=4%5E%7B-0%7D%20%3D%201)
when x = 2, ![4^{-2} = \frac{1}{16}](https://tex.z-dn.net/?f=4%5E%7B-2%7D%20%3D%20%5Cfrac%7B1%7D%7B16%7D)
when x = 4, ![4^{-4} = \frac{1}{256}](https://tex.z-dn.net/?f=4%5E%7B-4%7D%20%3D%20%5Cfrac%7B1%7D%7B256%7D)
For table two, we are to substitute the given values of x in the term
:
when x = 0, ![(\frac{2}{3} )^0 = 1](https://tex.z-dn.net/?f=%28%5Cfrac%7B2%7D%7B3%7D%20%29%5E0%20%3D%201%20)
when x = 2, ![(\frac{2}{3} )^2 = \frac{4}{9}](https://tex.z-dn.net/?f=%28%5Cfrac%7B2%7D%7B3%7D%20%29%5E2%20%3D%20%5Cfrac%7B4%7D%7B9%7D%20)
when x = 4, ![(\frac{2}{3} )^4 = \frac{16}{81}](https://tex.z-dn.net/?f=%28%5Cfrac%7B2%7D%7B3%7D%20%29%5E4%20%3D%20%5Cfrac%7B16%7D%7B81%7D%20)
Not sure. Sorry! I will edit when I get an answer.
Answer:
Step-by-step explanation:
P (x) = ( x + 2 ) ( x - 3 ) ( x + 7 )
(x^2 - 3x + 2x - 6) ( x + 7 )
( x^2 - x - 6 ) ( x + 7 )
( x^3 + 7x^2 - x^2 - 7x - 6x - 42 )
(x^3 + 6x^2 - 13x - 42)
The constant term in this function is - 42.
( A constant term is a term in an algebraic expression that has a value that is constant or cannot change, because it does not contain any modifiable variables. )
I hope this helps!