Answer:
D
Explanation:
You can search it on the internet if you're still not sure
Hope I helped youu
Answer:
x = 9/25, y = 7/25, z = 4/25
Explanation:
step 1: solve for y in first equation to use substitution
y = -2x + 1
step 2: insert into second equation to eliminate y variable and work with two variables
3(-2x+1) + z = 1 (now distribute)
-6x + 3 + z = 1 (bring over the -3)
-6x + z = -2
step 3: now left with -6x + z = -2 and x + 4z = 1, so eliminate z
-6x + z = -2 (multiply by 4)
4(-6x + z = -2)
-24x + 4z = -8
-
x + 4z = 1 (brought down third equation)
-25x = -9
x = 9/25
then just plug in x into the third equation to solve for z, followed by plugging it into the first equation to solve for y. you should end with y = 7/25 and z = 4/25
Answer:
double a;
double b;
double distance = Math.sqrt( (Math.pow(a, 2) + Math.pow(b, 2));
System.out.println("The distance is: " + distance);
Explanation:
The code snippet is written in Java.
First, variable a is declared as a type of double and variable b is also declared as a type of double.
The given formula for the distance is:
√(a² + b²)
So we use the inbuilt function of Java to calculate the power and the square root.
Math.sqrt is to find the square root and it returns a value of type double.
Math.pow is use to calculate the value of a² and b².
a² = Math.pow(a, 2)
b² = Math.pow(b, 2)
Then Math.sqrt is applied to the sum of Math.pow(a, 2) and Math.pow(b, 2), the value is assigned to distance of type double.
The value of distance is now displayed to the user:
System.out.println("The distance is: " + distance);
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What ever they are comfortable paying.
More information is required to answer this problem properly.