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3 years ago

Solve the equation using square roots. x2 – 14 = –10

Mathematics

2 answers:

son4ous [18]3 years ago

7 0

Answer:-12

Step-by-step explanation:

Add 10+14 to get 24 then divide it by a negative 2 to get -12

olga nikolaevna [1]3 years ago

6 0

Answer:

x = ±2

Step-by-step explanation:

x^2 – 14 = –10

Add 14 to each side

x^2 – 14+14 = –10+14

x^2 = 4

Take the square root of each side

sqrt(x^2) = ±sqrt(4)

x = ±2

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Explanation:

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4 years ago

Read 2 more answers

Evaluate the summation of 3 n plus 2, from n equals 1 to 14. 39 49 340 343.

lord [1]

The summation of the considered expression in terms of n from n = 1 to 14 is given by: Option D: 343

<h3>How to find the sum of consecutive integers?</h3>

$1 + 2 + 3 + ... + n = \dfrac{n(n+1)}{2}$

<h3>
What are the properties of summation?</h3>

$\sum_{i=r}^s (a \times f(i) + b) = a \times [\: \sum_{i=r}^s f(i)] + (s-r)b$

where a, b, r, and s are constants, f(i) is function of i, i ranging from r to s (integral assuming).

For the given case, the considered summation can be written symbolically as:

$\sum_{n=1}^{14} (3n + 2)$

It is evaluated as;

$\sum_{n=1}^{14} (3n + 2) = 3 \times [ \: \sum_{n=1}^{14} n ] + \sum_{n=1}^{14} 2\\\\\sum_{n=1}^{14} (3n + 2) = 3 \times \dfrac{(14)(14 + 1)}{2} + (2 + 2 + .. + 2(\text{14 times}))\\\\\sum_{n=1}^{14} (3n + 2) = 3 \times 105 + 28 = 343\\$